qq_36424540 2017-08-02 11:19 采纳率: 87.5%
浏览 1012
已采纳

希望大神解答一下,这道题用bfs+优先队列为什么不对,只能用最短路径来写

Bessie and the rest of Farmer John's cows are taking a trip this winter to go skiing. One day Bessie finds herself at the top left corner of an R (1 <= R <= 100) by C (1 <= C <= 100) grid of elevations E (-25 <= E <= 25). In order to join FJ and the other cows at a discow party, she must get down to the bottom right corner as quickly as she can by travelling only north, south, east, and west.

Bessie starts out travelling at a initial speed V (1 <= V <= 1,000,000). She has discovered a remarkable relationship between her speed and her elevation change. When Bessie moves from a location of height A to an adjacent location of eight B, her speed is multiplied by the number 2^(A-B). The time it takes Bessie to travel from a location to an adjacent location is the reciprocal of her speed when she is at the first location.

Find the both smallest amount of time it will take Bessie to join her cow friends.

Input
* Line 1: Three space-separated integers: V, R, and C, which respectively represent Bessie's initial velocity and the number of rows and columns in the grid.

* Lines 2..R+1: C integers representing the elevation E of the corresponding location on the grid. 

Output
A single number value, printed to two exactly decimal places: the minimum amount of time that Bessie can take to reach the bottom right corner of the grid.
Sample Input

1 3 3
1 5 3
6 3 5
2 4 3

Sample Output

29.00

Hint
Bessie's best route is:
Start at 1,1 time 0 speed 1
East to 1,2 time 1 speed 1/16
South to 2,2 time 17 speed 1/4
South to 3,2 time 21 speed 1/8
East to 3,3 time 29 speed 1/4

  • 写回答

1条回答 默认 最新

      报告相同问题?

      相关推荐 更多相似问题

      悬赏问题

      • ¥20 kinect 使用 unity 开发使用手势旋转相机
      • ¥20 一个关于人脸识别的实训报告
      • ¥50 LoopyCuts编译运行问题
      • ¥20 VS2019如何添加.mdf文件失败
      • ¥15 SeaTunnel多Transform配置问题
      • ¥15 消除字符串,求最短字符串长度
      • ¥20 有人做基于集员滤波的异常值处理相关的内容吗?(语言-matlab)
      • ¥30 matlab编程,用chatGPT帮助,但给出的code总是报错。
      • ¥15 离线安装VS2017出现报错
      • ¥50 opengl2怎么将梯形的纹理映射在矩形上面不变形