怎么才能循环输出给定范围内的合数和质数？

Question

#include
#include
#include
#include
using namespace std;
void Prime() {
int k;
vector dv1;
vector dv2;
vector::iterator n;
vector::iterator m;
do{
cout << "请输入范围限定值c:" << " "; cin >> k;
if (!cin >> k) {
cout << "输入无效，请输入正确的数据！" << endl;
continue;
}
for (int i = 1; i <= k; ++i) {
int j = 2;
for (; j <= sqrt(i); ++j) {
if (i%j == 0)//用平方根以内的数去除，如果能除尽，则说明是合数，则跳出此次循环，此时i加1
//如果j自增到平方根还不能除尽，则j加1，说明是质数，此时j=sqrt(i)+1，自动跳出本循环
break;
}
if (j > sqrt(i) && i != 1) //j=sqrt(i)+1时说明i为质数，符合这个if条件，执行输出语句
dv1.push_back(i);
//cout << j <<endl;此为测试j值语句
else if (j <= sqrt(i) && i != 1)
dv2.push_back(i);
}

        cout << "质数为：" << " ";
        for (n = dv1.begin(); n != dv1.end(); n++)
            cout << *n << " ";
        cout << endl;
        cout << "合数为：" << " ";
        for (m = dv2.begin(); m != dv2.end(); m++)
            cout << *m << " ";
        cout << endl;

        dv1.clear();
        dv2.clear();

} while (cin >> k);

}
void main() {
Prime();
}
不通过反复系统调用，而是直接压缩到一个函数内解决，错误程序如下，求帮忙改正一下，谢谢！

Answer 1

http://blog.csdn.net/susan19890313/article/details/7436998