代码能运行，但添加信息时显示错误，不知道哪错了，求大佬帮忙改正正确的？

import javax.swing.*; import java.awt.*; import java.awt.event.*; import java.io.*; import java.util.*; class Note implements Serializable{ public String name; public String address; public String telephone; public Note(){} } public class AddressListSystem extends JFrame{ JLabel title=new JLabel("我的通讯录管理"); JLabel name=new JLabel("姓名"); JLabel address=new JLabel("地址"); JLabel telephone=new JLabel("电话"); JTextField jtxtname=new JTextField(); JTextField jtxtaddr=new JTextField(); JTextField jtxttel=new JTextField(); Font font=new Font("TimersRoman",Font.BOLD,30); JButton jbtadd=new JButton("添加"); JButton jbtfind=new JButton("查找"); JButton jbtclear=new JButton("清空"); JButton jbtexit=new JButton("退出"); ArrayList al=new ArrayList(); AddressListSystem(String s){ super(s); Container cp=getContentPane(); cp.setBackground(Color.PINK); cp.setLayout(null); title.setFont(font); title.setForeground(Color.BLUE); title.setBounds(130,20,300,60); name.setBounds(50,150,75,25); address.setBounds(50,220,75,25); telephone.setBounds(50,310,75,25); jtxtname.setBounds(150,150,100,25); jtxtaddr.setBounds(150,220,100,25); jtxttel.setBounds(150,310,200,25); jbtadd.setBounds(50,400,75,25); jbtfind.setBounds(150,400,75,25); jbtclear.setBounds(250,400,75,25); jbtexit.setBounds(350,400,75,25); jbtadd.addActionListener(new ActionListener(){ public void actionPerformed(ActionEvent e){ if(jtxtname.getText().equalsIgnoreCase("")){ JOptionPane.showMessageDialog(null,"无法添加名字为空的记录","错误提示",JOptionPane.INFORMATION_MESSAGE); jtxtname.setText(""); jtxtaddr.setText(""); jtxttel.setText(""); return; } Note note=new Note(); note.name=jtxtname.getText(); note.address=jtxtaddr.getText(); note.telephone=jtxttel.getText(); try{ ObjectInputStream in=new ObjectInputStream(new FileInputStream("note.dat")); al=(ArrayList)in.readObject(); in.close(); }catch(Exception ex){ System.out.println( "添加信息时文件输入有误哦"); } try{ ObjectOutputStream out=new ObjectOutputStream(new FileOutputStream("note.dat",true)); Note temp=new Note(); int i; for(i=0;i<al.size();i++){ temp=(Note)al.get(i); if(temp.name.equalsIgnoreCase(jtxtname.getText())) break; } if(!al.isEmpty()&&i!=al.size()){ JOptionPane.showMessageDialog(null,"已经存在此记录","错误提示",JOptionPane.INFORMATION_MESSAGE); } else{ al.add(note); out.writeObject(al); } out.close(); }catch(Exception ex){ System.out.println("添加信息时文件输出有误哦"); } jtxtname.setText(""); jtxtaddr.setText(""); jtxttel.setText(""); } }); jbtfind.addActionListener(new ActionListener(){ public void actionPerformed(ActionEvent e){ try{ ObjectInputStream in=new ObjectInputStream(new FileInputStream("note.dat")); al=(ArrayList)in.readObject(); in.close(); }catch(Exception ex){ System.out.println("查询时文件打开有误哦"); } Note temp=new Note(); int i; for(i=0;i<al.size();i++){ temp=(Note)al.get(i); if(temp.name.equalsIgnoreCase(jtxtname.getText())) break; } if(!al.isEmpty()&&i!=al.size()){ jtxtaddr.setText(temp.address); jtxttel.setText(temp.telephone); } else{ jtxtname.setText(""); jtxtaddr.setText(""); jtxttel.setText(""); JOptionPane.showMessageDialog(null,"无此记录哦","温馨提示",JOptionPane.INFORMATION_MESSAGE); } } }); jbtclear.addActionListener(new ActionListener(){ public void actionPerformed(ActionEvent e){ try{ ObjectOutputStream out=new ObjectOutputStream(new FileOutputStream("note.dat")); al.clear(); out.close(); }catch(Exception ex){ System.out.println("清除文件时有误哦"); } jtxtname.setText(""); jtxtaddr.setText(""); jtxttel.setText(""); } }); jbtexit.addActionListener(new ActionListener(){ public void actionPerformed(ActionEvent e){ try{ System.exit(1); }catch(Exception ex){ System.out.println("退出系统时出错啦"); } } }); cp.add(title); cp.add(name); cp.add(address); cp.add(telephone); cp.add(jtxtname); cp.add(jtxtaddr); cp.add(jtxttel); cp.add(jbtadd); cp.add(jbtfind); cp.add(jbtclear); cp.add(jbtexit); } public static void main(String[] args) { AddressListSystem als=new AddressListSystem("我的通讯录管理系统"); als.addWindowListener(new WindowAdapter(){ @Override public void windowClosing(WindowEvent e){ System.exit(0); } }); als.setSize(500,550); als.setVisible(true); } }

Snooker Referee 裁判的问题

Problem Description Snooker is a cue sport that is played on a large baize-covered table with pockets in each of the four corners and in the middle of each of the long side cushions. It is played using a cue and snooker balls: one white cue ball, 15 red balls worth one point each, and six balls of different colors: yellow (2 points), green (3), brown (4), blue (5), pink (6) and black (7). A player (or team) wins a frame (individual game) of snooker by scoring more points than the opponent(s), using the cue ball to pot the red and colored balls. In this problem, your job is the referee of snooker. You should score both players, ask the correct player to play next, as well as place some of the balls back to the table if necessary. The rules of snooker needed for this problem are following. (We ignore some fouls about incorrectly hitting the cue ball here. We assume that the cue ball is never snookered after a foul, so free ball will never occur. We also assume that both players will make their best attempts to hit the ball on, so you do not need to declare a miss when they do not hit the ball on first.) At the beginning of each frame the balls are set up by the referee as illustrated above. This will be followed by a break-off shot, the white cue ball can be placed anywhere inside the D (it is called in-hand, which also happens when the cue ball is potted). Players take turns in visiting the table. A break is the number of points scored by a player in one single visit to the table. A player's turn and break end when he fails to pot a ball, when he does something against the rules of the game, which is called a foul, or when a frame has ended. The ball or balls that can be hit first by the white are called the ball(s) "on" for that particular stroke. The ball(s) "on" differ from shot to shot: a red ball, if potted, must be followed by a color, and so on until a break ends; if a red is not potted, any red ball remains the ball "on". Only a ball or balls "on" may be potted legally by a player. If a ball not "on" is potted, this is a foul. The game of snooker generally consists of two phases. The first phase is the situation in which there are still red balls on the table. In the first phase, at the beginning of a player's turn, the balls "on" are all remaining red balls. The player must therefore attempt to first hit and pot one or more red balls. For every red ball potted, the player will receive 1 point. When a red has been potted, it will stay off the table and the player can continue his break. If no red has been potted or a foul has been made, the other player will come into play. In case one or more red balls have been potted, the player can continue his break. This time one of the six colors (yellow, green, brown, blue, pink and black) is the ball "on". Only one of these can be the ball "on" and the rules of the game state that a player must nominate his desired color to the referee, although it is often clear which ball the striker is playing and it is not necessary to nominate. When the nominated color is potted, the player will be awarded the correct number of points (yellow, 2; green, 3; brown, 4; blue, 5; pink, 6; black, 7). The color is then taken out of the pocket by the referee and placed on its original spot. Because only one of the colors is the ball "on", it is a foul to first hit multiple colors at the same time, or pot more than one color. If a player fails to pot a ball "on", it being a red or nominated color, the other player will come into play and the balls "on" are always the reds, as long as there are still reds on the table. The alternation between red balls and colors ends when all reds have been potted and a color is potted after the last red, or a failed attempt to do so is made. Then the second phase begins. All six colors have to be potted in ascending order of their points value (yellow, green, brown, blue, pink, black). Each becomes the ball "on" in that order. During this phase, when potted, the colors stay down and are not replaced on the table, unless a foul is made when potting the color, in which case the color is respotted. When only the black is left, the first score or foul ends the frame, and the player who has scored most points has won it. However, if the score is tied after that, the black is respotted, the players draw lots for choice of playing, the next player plays from in-hand, and the next score or foul ends the frame. When a foul is made during a shot, the player's turn is ended and he will receive no points for the foul shot. The other player will receive penalty points. Colors illegally potted are respotted (while reds are not), and if the cue ball is potted, the next player will play from in-hand. Fouls concerned in this problem are: 。failing to hit any other ball with the cue ball 。first hitting a ball "not-on" with the cue ball 。potting a ball "not-on" 。potting the white (in-off) Penalty points are at least 4 points and at most 7 points. The number of penalty points is the value of the ball "on", or any of the "foul" balls, whichever is highest. When more than one foul is made, the penalty is not the added total - only the most highly valued foul is counted. As players usually do not nominate a color explicitly when hitting the colors, please be tolerant and assume that he always nominate the ball with the lowest score when it cannot be deduced from the ball first hit (i.e. when the cue ball does not hit any ball or hit a red first). If a player commits a foul, and his opponent considers that the position left is unattractive, he may request that the offender play again from the resulting position. Input The input file contains multiple test cases. The first line of the input file is a single integer T (T ≤ 200), the number of test cases. For each test case (frame), the first line contains the names of the two players separated by a whitespace. The first player will take the break-off shot. Each name is made up of no more than 20 English letters, and the two names are different. After that, the input mainly consists of lines that describe a stroke each (with two exceptions stated later). A stroke is described by the color of the ball first hit by the cue ball (or "None" if the cue ball does not hit any ball), followed by zero or more colors of the balls potted, all separated by whitespaces. For example, a line "Red Red White Red" means the cue ball first hit a red ball, and 2 reds are potted as well as the cue ball itself; and a line "None" means the cue ball does not hit any ball thus no ball is potted. You can assume that all strokes are legal according to the balls remain on the table, and the cue ball will not hit two or more ball first simultaneously. A line "Play again" may appear if and only if the last stroke is a foul. It means the other player request that the offender play again from the resulting position. If a score or foul occurs when only the black is left, and the score is tied after that, a line with either player's name will follow. That means the player will play next as a result of the lot. The case end when the frame ends. There is a blank line before every test case. Output For each frame, print a line in the format "Frame K" first, where K is the index of this case starts from 1. Then use the output to indicate the referee's behaviors: 。When a frame begins, print a line in the format "PlayerName's turn, in-hand", where PlayerName is the name of the player who take the break-off shot. 。After each stroke, print a line "Foul!" first if it is a foul. Then print a line with current score in the format "ScoreA : ScoreB", where ScoreA is the score of the player who take the break-off shot, and ScoreB is the other player's score. After that, if the frame continue fairly (i.e. not only black is left before the stroke, or it is not a score or foul when only black is left), and some ball(s) should be respotted. Print a line with the word "Respot" following by the color(s) of the ball(s), all separated by whitespace. If more than one ball should be respotted, print their colors in ascending order of their values. Do not print anything if no ball needed to be respotted. At last (when the frame continue fairly and any necessary ball has been respotted), if the last player's break ends, print a line in the format "PlayerName's turn" to ask the other player to play next, where PlayerName is the next player's name. If the next player should play from in-hand, print "PlayerName's turn, in-hand" instead. 。After a foul, if the other player request that the offender play again, just print a line "PlayerName's turn" or "PlayerName's turn, in-hand" according to whether the cue ball is in-hand, where PlayerName is the offender's name. Note that the requester is actually requesting in his turn, after you asked him to play next. 。If a score or foul occurs when only the black is left, and the score is tied after that, print a line "Tie" after the score. Then print two lines "Respot Black" and "PlayerName's turn, in-hand" to respot the black and play from in-hand, where PlayerName is the next player's name (determined by the lot). 。When the frame ends, print a line "PlayerName wins" after the score, where PlayerName is the winner's name. Print a blank line between every two successive cases. Sample Input 1 Zero Maxbreak Red White Red Red Black Black Red Red Black Black Red Red Black Black Red Red Black Black Red Red Black Black Red Red Black Black Red Red Black Black Red Red Black Black Red Red Black Black Red Red Black Black Red Red Black Black Red Red Black Black Sample Output Frame 1 Zero's turn, in-hand Foul! 0 : 4 Maxbreak's turn, in-hand 0 : 5 0 : 12 Respot Black 0 : 13 0 : 20 Respot Black 0 : 21 0 : 28 Respot Black 0 : 29 0 : 36 Respot Black 0 : 37 0 : 44 Respot Black 0 : 45 0 : 52 Respot Black 0 : 53 0 : 60 Respot Black 0 : 61 0 : 68

Mod Tree 的具体的实现方法

Problem Description The picture indicates a tree, every node has 2 children. The depth of the nodes whose color is blue is 3; the depth of the node whose color is pink is 0. Now out problem is so easy, give you a tree that every nodes have K children, you are expected to calculate the minimize depth D so that the number of nodes whose depth is D equals to N after mod P. Input The input consists of several test cases. Every cases have only three integers indicating K, P, N. (1<=K, P, N<=10^9) Output The minimize D. If you can’t find such D, just output “Orz,I can’t find D!” Sample Input 3 78992 453 4 1314520 65536 5 1234 67 Sample Output Orz,I can’t find D! 8 20

Mod Tree 树的问题

Problem Description The picture indicates a tree, every node has 2 children. The depth of the nodes whose color is blue is 3; the depth of the node whose color is pink is 0. Now out problem is so easy, give you a tree that every nodes have K children, you are expected to calculate the minimize depth D so that the number of nodes whose depth is D equals to N after mod P. Input The input consists of several test cases. Every cases have only three integers indicating K, P, N. (1<=K, P, N<=10^9) Output The minimize D. If you can’t find such D, just output “Orz,I can’t find D!” Sample Input 3 78992 453 4 1314520 65536 5 1234 67 Sample Output Orz,I can’t find D! 8 20

利用 javascript 无法获取html 中 input 的 value 值

``` html <form> <input class="mdui-textfield-input" id="U-psd" type="password" required/> <button class="mdui-btn mdui-btn-raised mdui-color-pink mdui-ripple" type="submit" onclick="logon()">登陆</button> <form> ``` 在 js 中： ``` javascript const userPassword = document.getElementById("U-psd"); function login() { let loginUser = new User(userEmail.value, userPassword.value); console.log(userEmail.value); } ``` 在 chrome 中设置的断点，命中时报空字符串错误。 > checkForm.js:32 Uncaught TypeError: Cannot read property 'value' of null 求大佬指导。

Snooker Referee 比赛裁判的算法

Problem Description Snooker is a cue sport that is played on a large baize-covered table with pockets in each of the four corners and in the middle of each of the long side cushions. It is played using a cue and snooker balls: one white cue ball, 15 red balls worth one point each, and six balls of different colors: yellow (2 points), green (3), brown (4), blue (5), pink (6) and black (7). A player (or team) wins a frame (individual game) of snooker by scoring more points than the opponent(s), using the cue ball to pot the red and colored balls. In this problem, your job is the referee of snooker. You should score both players, ask the correct player to play next, as well as place some of the balls back to the table if necessary. The rules of snooker needed for this problem are following. (We ignore some fouls about incorrectly hitting the cue ball here. We assume that the cue ball is never snookered after a foul, so free ball will never occur. We also assume that both players will make their best attempts to hit the ball on, so you do not need to declare a miss when they do not hit the ball on first.) At the beginning of each frame the balls are set up by the referee as illustrated above. This will be followed by a break-off shot, the white cue ball can be placed anywhere inside the D (it is called in-hand, which also happens when the cue ball is potted). Players take turns in visiting the table. A break is the number of points scored by a player in one single visit to the table. A player's turn and break end when he fails to pot a ball, when he does something against the rules of the game, which is called a foul, or when a frame has ended. The ball or balls that can be hit first by the white are called the ball(s) "on" for that particular stroke. The ball(s) "on" differ from shot to shot: a red ball, if potted, must be followed by a color, and so on until a break ends; if a red is not potted, any red ball remains the ball "on". Only a ball or balls "on" may be potted legally by a player. If a ball not "on" is potted, this is a foul. The game of snooker generally consists of two phases. The first phase is the situation in which there are still red balls on the table. In the first phase, at the beginning of a player's turn, the balls "on" are all remaining red balls. The player must therefore attempt to first hit and pot one or more red balls. For every red ball potted, the player will receive 1 point. When a red has been potted, it will stay off the table and the player can continue his break. If no red has been potted or a foul has been made, the other player will come into play. In case one or more red balls have been potted, the player can continue his break. This time one of the six colors (yellow, green, brown, blue, pink and black) is the ball "on". Only one of these can be the ball "on" and the rules of the game state that a player must nominate his desired color to the referee, although it is often clear which ball the striker is playing and it is not necessary to nominate. When the nominated color is potted, the player will be awarded the correct number of points (yellow, 2; green, 3; brown, 4; blue, 5; pink, 6; black, 7). The color is then taken out of the pocket by the referee and placed on its original spot. Because only one of the colors is the ball "on", it is a foul to first hit multiple colors at the same time, or pot more than one color. If a player fails to pot a ball "on", it being a red or nominated color, the other player will come into play and the balls "on" are always the reds, as long as there are still reds on the table. The alternation between red balls and colors ends when all reds have been potted and a color is potted after the last red, or a failed attempt to do so is made. Then the second phase begins. All six colors have to be potted in ascending order of their points value (yellow, green, brown, blue, pink, black). Each becomes the ball "on" in that order. During this phase, when potted, the colors stay down and are not replaced on the table, unless a foul is made when potting the color, in which case the color is respotted. When only the black is left, the first score or foul ends the frame, and the player who has scored most points has won it. However, if the score is tied after that, the black is respotted, the players draw lots for choice of playing, the next player plays from in-hand, and the next score or foul ends the frame. When a foul is made during a shot, the player's turn is ended and he will receive no points for the foul shot. The other player will receive penalty points. Colors illegally potted are respotted (while reds are not), and if the cue ball is potted, the next player will play from in-hand. Fouls concerned in this problem are: 。failing to hit any other ball with the cue ball 。first hitting a ball "not-on" with the cue ball 。potting a ball "not-on" 。potting the white (in-off) Penalty points are at least 4 points and at most 7 points. The number of penalty points is the value of the ball "on", or any of the "foul" balls, whichever is highest. When more than one foul is made, the penalty is not the added total - only the most highly valued foul is counted. As players usually do not nominate a color explicitly when hitting the colors, please be tolerant and assume that he always nominate the ball with the lowest score when it cannot be deduced from the ball first hit (i.e. when the cue ball does not hit any ball or hit a red first). If a player commits a foul, and his opponent considers that the position left is unattractive, he may request that the offender play again from the resulting position. Input The input file contains multiple test cases. The first line of the input file is a single integer T (T ≤ 200), the number of test cases. For each test case (frame), the first line contains the names of the two players separated by a whitespace. The first player will take the break-off shot. Each name is made up of no more than 20 English letters, and the two names are different. After that, the input mainly consists of lines that describe a stroke each (with two exceptions stated later). A stroke is described by the color of the ball first hit by the cue ball (or "None" if the cue ball does not hit any ball), followed by zero or more colors of the balls potted, all separated by whitespaces. For example, a line "Red Red White Red" means the cue ball first hit a red ball, and 2 reds are potted as well as the cue ball itself; and a line "None" means the cue ball does not hit any ball thus no ball is potted. You can assume that all strokes are legal according to the balls remain on the table, and the cue ball will not hit two or more ball first simultaneously. A line "Play again" may appear if and only if the last stroke is a foul. It means the other player request that the offender play again from the resulting position. If a score or foul occurs when only the black is left, and the score is tied after that, a line with either player's name will follow. That means the player will play next as a result of the lot. The case end when the frame ends. There is a blank line before every test case. Output For each frame, print a line in the format "Frame K" first, where K is the index of this case starts from 1. Then use the output to indicate the referee's behaviors: 。When a frame begins, print a line in the format "PlayerName's turn, in-hand", where PlayerName is the name of the player who take the break-off shot. 。After each stroke, print a line "Foul!" first if it is a foul. Then print a line with current score in the format "ScoreA : ScoreB", where ScoreA is the score of the player who take the break-off shot, and ScoreB is the other player's score. After that, if the frame continue fairly (i.e. not only black is left before the stroke, or it is not a score or foul when only black is left), and some ball(s) should be respotted. Print a line with the word "Respot" following by the color(s) of the ball(s), all separated by whitespace. If more than one ball should be respotted, print their colors in ascending order of their values. Do not print anything if no ball needed to be respotted. At last (when the frame continue fairly and any necessary ball has been respotted), if the last player's break ends, print a line in the format "PlayerName's turn" to ask the other player to play next, where PlayerName is the next player's name. If the next player should play from in-hand, print "PlayerName's turn, in-hand" instead. 。After a foul, if the other player request that the offender play again, just print a line "PlayerName's turn" or "PlayerName's turn, in-hand" according to whether the cue ball is in-hand, where PlayerName is the offender's name. Note that the requester is actually requesting in his turn, after you asked him to play next. 。If a score or foul occurs when only the black is left, and the score is tied after that, print a line "Tie" after the score. Then print two lines "Respot Black" and "PlayerName's turn, in-hand" to respot the black and play from in-hand, where PlayerName is the next player's name (determined by the lot). 。When the frame ends, print a line "PlayerName wins" after the score, where PlayerName is the winner's name. Print a blank line between every two successive cases. Sample Input 1 Zero Maxbreak Red White Red Red Black Black Red Red Black Black Red Red Black Black Red Red Black Black Red Red Black Black Red Red Black Black Red Red Black Black Red Red Black Black Red Red Black Black Red Red Black Black Red Red Black Black Red Red Black Black Sample Output Frame 1 Zero's turn, in-hand Foul! 0 : 4 Maxbreak's turn, in-hand 0 : 5 0 : 12 Respot Black 0 : 13 0 : 20 Respot Black 0 : 21 0 : 28 Respot Black 0 : 29 0 : 36 Respot Black 0 : 37 0 : 44 Respot Black 0 : 45 0 : 52 Respot Black 0 : 53 0 : 60 Respot Black 0 : 61 0 : 68

Let the Balloon Rise II 是怎么来实现的

Problem Description Contest will be end at 17:00! How excited it is to see balloons floating around. I knew you had solved the HDOJ 1004 Let the Balloon Rise already, so please settle the another version quickly. I have a lot of balloons and each has a color and I give each of them a number, same color has the same number. For example, red balloon is No.1, pink is No.2, black is No.3 . etc. I also have many rooms to store all the balloons. There are some rules : 1. Every room stores several balloons but no two have the same color. 2. Collect all the balloons, we can find each color has even number of times of balloons except one. Your task is to find which is the odd color and calculate its number of times. Input Input file consists from multiple data sets separated by one or more empty lines. Each data set represents a sequence of 32-bit (positive) integers (references) which are stored in compressed way. Each line of input set consists from three single space separated 32-bit (positive) integers X Y Z and they represent following sequence of No.X, X+Z, X+2*Z, X+3*Z, …, X+K*Z, …(while (X+K*Z)<=Y). This line represents that in this room there exists (K+1) balloons whose No. is No.X, No.X+Z, No.X+2*Z, No.X+3*Z, …, No.X+K*Z, …etc. Output For each input data set you should print to standard output new line of text with two integers separated by single space (first one is No. that occurs odd number of times and second one is count of that kind of balloon). If all have even number of times output “None.” Sample Input 1 10 1 1 10 1 1 5 1 6 10 1 1 10 1 4 4 1 1 5 1 2 5 1 2 5 1 2 5 1 Sample Output None. 4 3 1 1

Counting Problem 技术问题

Problem Description See the 2 X 2 board above. AekdyCoin gets a N X N chessboard recently. But he think the color of the chessman is too dull (Only White and Black!).So AekdyCoin buys different kind of chessmen with different color, say blue, pink, yellow …Now AekdyCoin buys K kind of chessmen with different color, and the number of each kind is exactly Ai. Now AekdyCoin begins to play with these chessmen. He wants to put all the chessmen he bought on the board, and of course every grid could only contain one single chessman.The Figure 2 shows a valid situation ,in this figure, AekdyCoin bought two kind of chessmen and the number of each is one. As we know, AekdyCoin is very clever. So he think about this question:What is the number of ways he could put all chessmen he bought on the N X N board? After a several seconds , AekdyCoin gets a perfect idea about how to solve this problem. What about you? Two situation are regard the same in Figure 3, but the different in Figure 4. But the ways that you can get by flip or circumrotate is not regard as the same! Input The input consists of several test cases, but no more than 20. There are two integers N, M in the first line of each case indicate the size of the board and M. You should output the remainder of answer after divided by M. (1<=N <=5000, 1<=M<=2*10^9) The next line contain only one integer K indicates the kind of the chessmen AekdyCoin bought. (1<=k<=100) Then the next line has exactly K integer where the i-th integer Ai indicate the number of the i-th kind of chessmen AekdyCoin bought.(1<=Ai<=5000) Output Output a single line indicates the reaminder of answer after divided by M. Sample Input 2 100 1 1 2 100 1 2 Sample Output 4 6

Java题目，求大神帮忙看看怎么修改，一直有两处错误？

package tf1703; import java.awt.Color; import java.awt.Graphics; //import Tank.Direction; public class Tank { public int x,y,w,h; Enum Direction{L,LU,U,RU,R,RD,D,LD,STOP}; public Direction dir=Direction.U; public Tank(int x,int y,int w,int h,Direction dir) { this.x=x; this.y=y; this.w=w; this.h=h; this.dir=dir; } public void draw(Graphics g) { g.setColor(Color.green); g.fillOval(x,y,w,h); switch(this.dir) { case U: g.setColor(Color.black); g.drawLine(x+w/2, y+h/2, x+w/2, y-10); break; case LU: g.setColor(Color.black); g.drawLine(x+w/2, y+h/2, x, y); break; case L: g.setColor(Color.black); g.drawLine(x+w/2, y+h/2, x-10, y+h/2); break; case LD: g.setColor(Color.black); g.drawLine(x+w/2, y+h/2, x, y+h); break; case D: g.setColor(Color.black); g.drawLine(x+w/2, y+h/2, x+w/2, y+h+10); break; case RD: g.setColor(Color.black); g.drawLine(x+w/2, y+h/2, x+w, y+h); break; case R: g.setColor(Color.black); g.drawLine(x+w/2, y+h/2, x+w+10, y+h/2); break; case RU: g.setColor(Color.black); g.drawLine(x+w/2, y+h/2, x+w, y); break; } } } package tf1703; import java.awt.*; import java.awt.event.KeyAdapter; import java.awt.event.KeyEvent; import java.awt.event.WindowAdapter; import java.awt.event.WindowEvent; import tf1703.Tank.Direction; public class TFrame extends Frame{ public int frameX=100; public int frameY=100; public int frameH=800; public int frameW=1200; public Tank myTank=null; public TFrame() { this.setBounds(frameX,frameY,frameW,frameH); this.setBackground(Color.pink); this.myTank=new Tank(200,200,100,100,Tank.Direction.RU); this.addWindowListener(new WindowAdapter() { public void windowClosing(WindowEvent e) { System.exit(-1); } }); this.addKeyListener(new KeyAdapter() { public void keyPressed(KeyEvent e) { if(e.getKeyCode()==KeyEvent.VK_A) { System.out.println("你按了A"); myTank.dir=Direction.L; myTank.x=myTank.x-10; }else if(e.getKeyCode()==KeyEvent.VK_S) { System.out.println("你按了S"); myTank.dir=Direction.D; myTank.y=myTank.y+10; } else if(e.getKeyCode()==KeyEvent.VK_D) { System.out.println("你按了D"); myTank.dir=Direction.R; myTank.x=myTank.x+10; } else if(e.getKeyCode()==KeyEvent.VK_W) { System.out.println("你按了W"); myTank.dir=Direction.U; myTank.y=myTank.y-10; } repaint(); } }); this.setVisible(true); } public void paint(Graphics g) { this.myTank.draw(g); } public static void main(String[] args) { new TFrame(); } } Exception in thread "main" java.lang.Error: Unresolved compilation problems: The import tf1703.Tank.Direction cannot be resolved Cannot make a static reference to the non-static field Tank.Direction Direction cannot be resolved to a type Direction cannot be resolved to a variable Direction cannot be resolved to a type Direction cannot be resolved to a variable Direction cannot be resolved to a type Direction cannot be resolved to a variable Direction cannot be resolved to a type Direction cannot be resolved to a variable at tf1703.TFrame.<init>(TFrame.java:9) at tf1703.TFrame.main(TFrame.java:86)

Greed is good 代码的编程实现

Problem Description As we all know Uncle CTW is a very greedy uncle,he likes collecting jewels.One day he gets a necklace with beautiful gems,he has a strange habit,that he only collects the contiguous gems with with same color.That means if he pick a red gem at first,and he will continue to pick only if the next gem is red,or he will stop.(That's why people call him "Uncle.Strange"). As it is a necklace,he must find somewhere to cut the necklace at the very begining,then select an end to pick until meet a different color gem,and do the same for the other end (which might not be of the same color as the gems collected before this). There are only three kinds of gems,red('r'),pink('p'),and white('w'),and NOTICE that,because the white one could be painted,so it can be seen as either color.(See the sample for detail.) Now he just want to know the maximum number of gems he can collect,could you tell him? Input The first line contain an integer T,then T lines,each line with a string only contain r,p or w ,with length no more than 400. Output One integer per line indicating the maximum nunber. Sample Input 1 wwwpprwrprprrprprwrwwrpwrwrrp Sample Output 11

一个用java写的计算器求大神跟我 说说怎么实现除数不能为零 我弄的不对 好难过

public class Calculator { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub MyFrame1 myFrame=new MyFrame1(); } } class MyFrame1 extends JFrame{ public MyFrame1(){ setTitle("Calculator");//设置标题 setLocation(500, 300); //setSize(800, 600); Mypanel mypanel=new Mypanel(); add(mypanel); addWindowListener(new WindowAdapter(){@Override public void windowClosing(WindowEvent e) { // TODO Auto-generated method stub System.exit(0); } }); pack(); setVisible(true);//设置可见 } } class Mypanel extends JPanel{//计算器面板 private static final ActionListener CE_Action = null; JPanel panel_btn; JTextField textField; private String lastcommand;//记录最后一个运算符 private String result;//记录运算的操作数 private boolean start;//记录是否点击了运算符 private boolean flag1;//记录是否重复点击了运算符 private boolean point;//记录是否重复点击了小数点 private boolean operateValidFlag = true; //操作是否合法 private float resultNum = 0;// 中间数是零 private JTextField resultText = new JTextField("0");//计算结果文本框 public Mypanel(){ start=false; result= "0"; flag1=true; point=true; lastcommand ="="; setLayout(new BorderLayout());//四周型布局 textField=new JTextField();//文本框 textField.setHorizontalAlignment(JTextField.RIGHT);//右显示文本 textField.setEditable(false);//文本框不可编辑 add(textField,BorderLayout.NORTH); panel_btn=new JPanel(); //重新定义一个panel 用作按钮的面板 panel_btn.setLayout(new GridLayout(5, 4)); InsertAction insertAction=new InsertAction();//创建数字点击时事件的一个对象 CommandAction commandAction=new CommandAction();//创建运算符点击事件的一个对象 C_Action cAction =new C_Action(); CE_Action ceaAction = new CE_Action(); Back_Action back_Action = new Back_Action(); PressBPN pressBPN = new PressBPN(); addButton("←",back_Action); addButton("CE",ceaAction); addButton("C",cAction); addButton("±",pressBPN); addButton("7",insertAction); addButton("8",insertAction); addButton("9",insertAction); addButton("/",commandAction); addButton("4",insertAction); addButton("5",insertAction); addButton("6",insertAction); addButton("*",commandAction); addButton("1",insertAction); addButton("2",insertAction); addButton("3",insertAction); addButton("-",commandAction); addButton("0",insertAction); addButton(".",insertAction); addButton("=",commandAction); addButton("+",commandAction); add(panel_btn,BorderLayout.CENTER);//按钮面板添加到中间 } private void addButton(String label,ActionListener listener){ //添加计算器按钮到计算器面板上 JButton btn=new JButton(label); btn.addActionListener(listener);//注册事件 panel_btn.add(btn); btn.setForeground(Color.PINK); } private class InsertAction implements ActionListener{// 实现点击计算器键盘按钮的值 @Override public void actionPerformed(ActionEvent e) { if (start){ textField.setText(""); start=(false); } flag1=true; String s=e.getActionCommand();//获取按钮的文本 //textField.setText(textField.getText()+s); if((s.equals("."))&&(textField.getText().indexOf(".")<0)){ textField.setText(textField.getText()+"."); } else if(!s.equals(".")) textField.setText(textField.getText()+s); } } private class CommandAction implements ActionListener{//运算符的点击事件 @Override public void actionPerformed(ActionEvent e) { // TODO Auto-generated method stub calute(Float.parseFloat(textField.getText())); lastcommand=e.getActionCommand();//获取运算的符号 result=textField.getText();//获取按钮的内容 //pointAction(textField.getText()); //String xString=e.getActionCommand(); //float a1=Float.parseFloat(result);//第一个操作数 //float a2=Float.parseFloat(textField.getText()); if (lastcommand.equals("/")) { // 除法运算 // 如果除号后面的值是0 if( getNumberFromText()==0){ // 操作不合法 System.out.println("111"); //operateValidFlag=false; textField.setText("除数不能为零"); } else { resultNum /= getNumberFromText(); } } start=true; } } private void calute (Float f){ resultNum = Float.parseFloat(result); ///float a1=Float.parseFloat(result);//第一个操作数 float a3=resultNum;//最终结果 if(flag1){ if(lastcommand.equals("+")) a3=resultNum+f; else if(lastcommand.equals("-")) a3=resultNum-f; else if(lastcommand.equals("*")) a3=resultNum*f; else if(lastcommand.equals("/")) a3=resultNum/f; else if(lastcommand.equals("=")) a3=f; flag1=false; } if(Math.floor(a3)==a3){ textField.setText((int)a3+"");} else { textField.setText(a3+""); } start=true; } private class C_Action implements ActionListener{ @Override public void actionPerformed(ActionEvent e) { // TODO Auto-generated method stub start=false; result= "0"; flag1=true; lastcommand ="="; textField.setText(""); } } private class CE_Action implements ActionListener{ @Override public void actionPerformed(ActionEvent e) { // TODO Auto-generated method stub textField.setText(""); } } private class Back_Action implements ActionListener{ @Override public void actionPerformed(ActionEvent e) { // TODO Auto-generated method stub String s1 = textField.getText(); String s2 = s1.substring(0,s1.length()-1); textField.setText(s2); } } private float getNumberFromText() { // 获取当前文本框内的数值 float result = 0; try { result = Float.valueOf(resultText.getText()).floatValue(); } catch (NumberFormatException e) { } return result; } class PressBPN implements ActionListener { //正负号的实现 public void actionPerformed(ActionEvent e) { String text = textField.getText(); if (text != "") { if(text.charAt(0)=='-') textField.setText(text.substring(1)); else if(text.charAt(0) >= '0' && text.charAt(0) <= '9') textField.setText("-"+text.substring(0)); else if(text.charAt(0) == '.') textField.setText("-0"+text.substring(0)); } start=true; } } private class EqualsAction implements ActionListener{//等号运算的点击事件 public void actionPerformed (ActionEvent e){ } } }

为什么我做的登录页面的验证码，第一次总是加载不出来，要点击刷新才行？

   ++++++++++++++++++++++++++++++++++++++++++++++ <%@ page contentType="text/html;charset=UTF-8" language="java" %> <html> <head> <title>Title</title> </head> <body> <script> <%-- 当窗口加载完毕 --%> window.onload = function (ev) { document.getElementById("img").onclick = function (ev1) { this.src = "./checkCodeServlet?time="+new Date().getTime(); } } </script> <form action="./loginServlet"> <table> <tr> <td>账号</td> <td><input type="text" name="username"></td> </tr> <tr> <td>密码</td> <td><input type="password" name="password"></td> </tr> <tr> <td>验证码</td> <td><input type="text" name="checkCode"></td> </tr> <tr> <td colspan="2"><img id="img" src="com.test.pro.CheckCodeServlet"></td> </tr> <tr> <td>提交</td> <td colspan="2"><input type="submit" value="登录"></td> </tr> <tr> <td></td> <td></td> </tr> </table> </form> <div><%=request.getAttribute("cc_error") == null ? "" : request.getAttribute("cc_error") %></div> <div><%=request.getAttribute("login_error") == null ? "" : request.getAttribute("login_error")%></div> </body> </html> ++++++++++++++++++++++++++++++++++++++++++++++ @WebServlet("/checkCodeServlet") public class CheckCodeServlet extends HttpServlet { protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { int width = 100; int height = 50; //1.创建一对象，在内存中图片(验证码图片对象) BufferedImage image = new BufferedImage(width,height,BufferedImage.TYPE_INT_RGB); //2.美化图片 //2.1 填充背景色 Graphics g = image.getGraphics();//画笔对象 g.setColor(Color.PINK);//设置画笔颜色 g.fillRect(0,0,width,height); //2.2画边框 g.setColor(Color.BLUE); g.drawRect(0,0,width - 1,height - 1); String str = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghigklmnopqrstuvwxyz0123456789"; //生成随机角标 Random ran = new Random(); StringBuilder sb = new StringBuilder(); for (int i = 1; i <= 4; i++) { int index = ran.nextInt(str.length()); //获取字符 char ch = str.charAt(index);//随机字符 // 把生成的验证码存进sb sb.append(ch); //2.3写验证码 g.drawString(ch+"",width/5*i,height/2); } // 转换sb的格式？ String checkCode_session = sb.toString(); //将验证码存入session request.getSession().setAttribute("checkCode_session",checkCode_session); //2.4画干扰线 g.setColor(Color.GREEN); //随机生成坐标点 for (int i = 0; i < 10; i++) { int x1 = ran.nextInt(width); int x2 = ran.nextInt(width); int y1 = ran.nextInt(height); int y2 = ran.nextInt(height); g.drawLine(x1,y1,x2,y2); } //3.将图片输出到页面展示 ImageIO.write(image,"jpg",response.getOutputStream()); } protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { this.doPost(request,response); } }

Let the Balloon Rise

Problem Description Contest time again! How excited it is to see balloons floating around. But to tell you a secret, the judges' favorite time is guessing the most popular problem. When the contest is over, they will count the balloons of each color and find the result. This year, they decide to leave this lovely job to you. Input Input contains multiple test cases. Each test case starts with a number N (0 < N <= 1000) -- the total number of balloons distributed. The next N lines contain one color each. The color of a balloon is a string of up to 15 lower-case letters. A test case with N = 0 terminates the input and this test case is not to be processed. Output For each case, print the color of balloon for the most popular problem on a single line. It is guaranteed that there is a unique solution for each test case. Sample Input 5 green red blue red red 3 pink orange pink 0 Sample Output red pink

Greed is good 怎么写的

Problem Description As we all know Uncle CTW is a very greedy uncle,he likes collecting jewels.One day he gets a necklace with beautiful gems,he has a strange habit,that he only collects the contiguous gems with with same color.That means if he pick a red gem at first,and he will continue to pick only if the next gem is red,or he will stop.(That's why people call him "Uncle.Strange"). As it is a necklace,he must find somewhere to cut the necklace at the very begining,then select an end to pick until meet a different color gem,and do the same for the other end (which might not be of the same color as the gems collected before this). There are only three kinds of gems,red('r'),pink('p'),and white('w'),and NOTICE that,because the white one could be painted,so it can be seen as either color.(See the sample for detail.) Now he just want to know the maximum number of gems he can collect,could you tell him? Input The first line contain an integer T,then T lines,each line with a string only contain r,p or w ,with length no more than 400. Output One integer per line indicating the maximum nunber. Sample Input 1 wwwpprwrprprrprprwrwwrpwrwrrp Sample Output 11

Snooker Referee 请问是如何来实现的

Problem Description Snooker is a cue sport that is played on a large baize-covered table with pockets in each of the four corners and in the middle of each of the long side cushions. It is played using a cue and snooker balls: one white cue ball, 15 red balls worth one point each, and six balls of different colors: yellow (2 points), green (3), brown (4), blue (5), pink (6) and black (7). A player (or team) wins a frame (individual game) of snooker by scoring more points than the opponent(s), using the cue ball to pot the red and colored balls. In this problem, your job is the referee of snooker. You should score both players, ask the correct player to play next, as well as place some of the balls back to the table if necessary. The rules of snooker needed for this problem are following. (We ignore some fouls about incorrectly hitting the cue ball here. We assume that the cue ball is never snookered after a foul, so free ball will never occur. We also assume that both players will make their best attempts to hit the ball on, so you do not need to declare a miss when they do not hit the ball on first.) At the beginning of each frame the balls are set up by the referee as illustrated above. This will be followed by a break-off shot, the white cue ball can be placed anywhere inside the D (it is called in-hand, which also happens when the cue ball is potted). Players take turns in visiting the table. A break is the number of points scored by a player in one single visit to the table. A player's turn and break end when he fails to pot a ball, when he does something against the rules of the game, which is called a foul, or when a frame has ended. The ball or balls that can be hit first by the white are called the ball(s) "on" for that particular stroke. The ball(s) "on" differ from shot to shot: a red ball, if potted, must be followed by a color, and so on until a break ends; if a red is not potted, any red ball remains the ball "on". Only a ball or balls "on" may be potted legally by a player. If a ball not "on" is potted, this is a foul. The game of snooker generally consists of two phases. The first phase is the situation in which there are still red balls on the table. In the first phase, at the beginning of a player's turn, the balls "on" are all remaining red balls. The player must therefore attempt to first hit and pot one or more red balls. For every red ball potted, the player will receive 1 point. When a red has been potted, it will stay off the table and the player can continue his break. If no red has been potted or a foul has been made, the other player will come into play. In case one or more red balls have been potted, the player can continue his break. This time one of the six colors (yellow, green, brown, blue, pink and black) is the ball "on". Only one of these can be the ball "on" and the rules of the game state that a player must nominate his desired color to the referee, although it is often clear which ball the striker is playing and it is not necessary to nominate. When the nominated color is potted, the player will be awarded the correct number of points (yellow, 2; green, 3; brown, 4; blue, 5; pink, 6; black, 7). The color is then taken out of the pocket by the referee and placed on its original spot. Because only one of the colors is the ball "on", it is a foul to first hit multiple colors at the same time, or pot more than one color. If a player fails to pot a ball "on", it being a red or nominated color, the other player will come into play and the balls "on" are always the reds, as long as there are still reds on the table. The alternation between red balls and colors ends when all reds have been potted and a color is potted after the last red, or a failed attempt to do so is made. Then the second phase begins. All six colors have to be potted in ascending order of their points value (yellow, green, brown, blue, pink, black). Each becomes the ball "on" in that order. During this phase, when potted, the colors stay down and are not replaced on the table, unless a foul is made when potting the color, in which case the color is respotted. When only the black is left, the first score or foul ends the frame, and the player who has scored most points has won it. However, if the score is tied after that, the black is respotted, the players draw lots for choice of playing, the next player plays from in-hand, and the next score or foul ends the frame. When a foul is made during a shot, the player's turn is ended and he will receive no points for the foul shot. The other player will receive penalty points. Colors illegally potted are respotted (while reds are not), and if the cue ball is potted, the next player will play from in-hand. Fouls concerned in this problem are: 。failing to hit any other ball with the cue ball 。first hitting a ball "not-on" with the cue ball 。potting a ball "not-on" 。potting the white (in-off) Penalty points are at least 4 points and at most 7 points. The number of penalty points is the value of the ball "on", or any of the "foul" balls, whichever is highest. When more than one foul is made, the penalty is not the added total - only the most highly valued foul is counted. As players usually do not nominate a color explicitly when hitting the colors, please be tolerant and assume that he always nominate the ball with the lowest score when it cannot be deduced from the ball first hit (i.e. when the cue ball does not hit any ball or hit a red first). If a player commits a foul, and his opponent considers that the position left is unattractive, he may request that the offender play again from the resulting position. Input The input file contains multiple test cases. The first line of the input file is a single integer T (T ≤ 200), the number of test cases. For each test case (frame), the first line contains the names of the two players separated by a whitespace. The first player will take the break-off shot. Each name is made up of no more than 20 English letters, and the two names are different. After that, the input mainly consists of lines that describe a stroke each (with two exceptions stated later). A stroke is described by the color of the ball first hit by the cue ball (or "None" if the cue ball does not hit any ball), followed by zero or more colors of the balls potted, all separated by whitespaces. For example, a line "Red Red White Red" means the cue ball first hit a red ball, and 2 reds are potted as well as the cue ball itself; and a line "None" means the cue ball does not hit any ball thus no ball is potted. You can assume that all strokes are legal according to the balls remain on the table, and the cue ball will not hit two or more ball first simultaneously. A line "Play again" may appear if and only if the last stroke is a foul. It means the other player request that the offender play again from the resulting position. If a score or foul occurs when only the black is left, and the score is tied after that, a line with either player's name will follow. That means the player will play next as a result of the lot. The case end when the frame ends. There is a blank line before every test case. Output For each frame, print a line in the format "Frame K" first, where K is the index of this case starts from 1. Then use the output to indicate the referee's behaviors: 。When a frame begins, print a line in the format "PlayerName's turn, in-hand", where PlayerName is the name of the player who take the break-off shot. 。After each stroke, print a line "Foul!" first if it is a foul. Then print a line with current score in the format "ScoreA : ScoreB", where ScoreA is the score of the player who take the break-off shot, and ScoreB is the other player's score. After that, if the frame continue fairly (i.e. not only black is left before the stroke, or it is not a score or foul when only black is left), and some ball(s) should be respotted. Print a line with the word "Respot" following by the color(s) of the ball(s), all separated by whitespace. If more than one ball should be respotted, print their colors in ascending order of their values. Do not print anything if no ball needed to be respotted. At last (when the frame continue fairly and any necessary ball has been respotted), if the last player's break ends, print a line in the format "PlayerName's turn" to ask the other player to play next, where PlayerName is the next player's name. If the next player should play from in-hand, print "PlayerName's turn, in-hand" instead. 。After a foul, if the other player request that the offender play again, just print a line "PlayerName's turn" or "PlayerName's turn, in-hand" according to whether the cue ball is in-hand, where PlayerName is the offender's name. Note that the requester is actually requesting in his turn, after you asked him to play next. 。If a score or foul occurs when only the black is left, and the score is tied after that, print a line "Tie" after the score. Then print two lines "Respot Black" and "PlayerName's turn, in-hand" to respot the black and play from in-hand, where PlayerName is the next player's name (determined by the lot). 。When the frame ends, print a line "PlayerName wins" after the score, where PlayerName is the winner's name. Print a blank line between every two successive cases. Sample Input 1 Zero Maxbreak Red White Red Red Black Black Red Red Black Black Red Red Black Black Red Red Black Black Red Red Black Black Red Red Black Black Red Red Black Black Red Red Black Black Red Red Black Black Red Red Black Black Red Red Black Black Red Red Black Black Sample Output Frame 1 Zero's turn, in-hand Foul! 0 : 4 Maxbreak's turn, in-hand 0 : 5 0 : 12 Respot Black 0 : 13 0 : 20 Respot Black 0 : 21 0 : 28 Respot Black 0 : 29 0 : 36 Respot Black 0 : 37 0 : 44 Respot Black 0 : 45 0 : 52 Respot Black 0 : 53 0 : 60 Respot Black 0 : 61 0 : 68

JAVA风景日历，运行时，日历是有了，但风景没有，这是为什么？

运行是这样  但是想要这样 ``` import java.awt.*; import java.awt.event.MouseAdapter; import java.awt.event.MouseEvent; import java.util.*; import java.util.Timer; import javax.swing.*; import javax.swing.event.*; import javax.swing.table.*; //这是一个用JList和JTable完成的简单日历 public class calender { public static void main(String[] args) { EventQueue.invokeLater(new Runnable() { public void run() { JFrame frame = new CalendarFrame(); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); frame.setVisible(true); } }); } } class CalendarFrame extends JFrame { private static final long serialVersionUID = 8067844586793608064L; JPanel listPanel; // 显示月份的列表面板 JPanel tablePanel; // 显示日期的表格面板 JPanel textPanel; // 文本面板 JMenuBar menuBar; // JMenuBar,JMenu定义的变量都没有实现功能 JMenu fileMenu; JMenu editMenu; JMenu formatMenu; JMenu lookMenu; JMenu helpMenu; JEditorPane text; // 自带复制，剪切和删除快捷键功能的面板 JScrollPane textscrollpane; JScrollPane tablescrollpane; @SuppressWarnings("rawtypes") JList list; // 显示月份的列表 JTable table; // 显示日期的表格 JPanel yearPanel; // 显示年份的面板 JSpinner spinner; // JSpinner空间 JLabel label = new JLabel(); public static boolean flag = true; @SuppressWarnings({ "unchecked", "rawtypes" }) public CalendarFrame() { table = new JTable(new MyTableModel()); tablescrollpane = new JScrollPane(table); for (int i = 0; i < 7; i++) { TableColumn column = table.getColumnModel().getColumn(i);// 获取表格每一列 column.setResizable(false);// 不允许改变列的大小 } table.setBackground(Color.GREEN); table.setRowHeight(72); // 设定每列的大小 table.setRowSelectionAllowed(false);// 设定行的选择模式 table.setDefaultRenderer(String.class, new MyTableRenderer()); list = new JList(new AbstractListModel() // 匿名的list模型类，提供list显示的月份数据 { private static final long serialVersionUID = -3703164069291737586L; public Object getElementAt(int index) { String obj = null; switch (index) { case 0: obj = "Jan"; break; case 1: obj = "Feb"; break; case 2: obj = "Mar"; break; case 3: obj = "Apr"; break; case 4: obj = "May"; break; case 5: obj = "Jun"; break; case 6: obj = "Jul"; break; case 7: obj = "Aug"; break; case 8: obj = "Sep"; break; case 9: obj = "Oct"; break; case 10: obj = "Nov"; break; case 11: obj = "Dec"; break; } return obj; } @Override public int getSize() { return 12; } }); list.setSelectionMode(ListSelectionModel.SINGLE_SELECTION); // 设定列表的选择模式 list.setCellRenderer(new MyListCellRenderer()); // 列表元素的绘制类MyListCellRenderer list.setSelectedIndex(Calendar.getInstance().get(Calendar.MONTH));// JList默认的月份为现实的月份 list.addListSelectionListener(new ListSelectionListener()// 当某个列表被选中时，更新日期table控件 { public void valueChanged(ListSelectionEvent e) { flag = true; table.updateUI(); } }); list.addMouseListener(new MouseAdapter() { public void mouseClicked(MouseEvent evt) { if (evt.getClickCount() == 2) { String s = (String) list.getSelectedValue(); JOptionPane.showMessageDialog(list, s); } } }); listPanel = new JPanel(); listPanel.setLayout(new BorderLayout()); listPanel.add(list); tablePanel = new JPanel(); tablePanel.setBackground(Color.white); tablePanel.setLayout(new BorderLayout()); tablePanel.add(tablescrollpane); // table.setBackground(Color.green); yearPanel = new JPanel();// 将label控件和JSpinner控件加入年份面板上 yearPanel.setLayout(new GridLayout(0, 4)); JLabel gongyuan = new JLabel("公元", JLabel.RIGHT); JLabel year = new JLabel("年"); spinner = new JSpinner(new SpinnerNumberModel(Calendar.getInstance() .get(Calendar.YEAR), null, null, 1)); spinner.addChangeListener(new ChangeListener() // 为JSpinner空间添加事件监听器 { @Override public void stateChanged(ChangeEvent e) { flag = true; table.updateUI(); } }); yearPanel.add(gongyuan); yearPanel.add(spinner); yearPanel.add(year); yearPanel.add(label); showTime(); new Timer().schedule(new TimerTask() { @Override public void run() { while (true) { showTime(); } } }, 1000); tablePanel.add(yearPanel, BorderLayout.NORTH);// 将年份面板加入到表格面板的北部 textPanel = new JPanel(); textPanel.setLayout(new BorderLayout()); text = new JEditorPane(); textscrollpane = new JScrollPane(text); textPanel.add(textscrollpane); text.setFont(new Font("SansSerif", Font.PLAIN, 40)); tablePanel.add(textPanel, BorderLayout.SOUTH); menuBar = new JMenuBar();// JMenu定义的空间都没实现功能 fileMenu = new JMenu("文件"); editMenu = new JMenu("编辑"); formatMenu = new JMenu("格式"); lookMenu = new JMenu("查看"); helpMenu = new JMenu("帮助"); menuBar.add(fileMenu); menuBar.add(editMenu); menuBar.add(formatMenu); menuBar.add(lookMenu); menuBar.add(helpMenu); GridBagLayout layout = new GridBagLayout(); // 设成GridBagLayout布局 GridBagConstraints constraints = new GridBagConstraints(); this.setFont(new Font("SansSerif", Font.PLAIN, 14)); this.setLayout(layout); this.setTitle("风景日历"); // 设定标题 this.setIconImage(new ImageIcon("res\\title.jpg").getImage()); // 设定图标 constraints.fill = GridBagConstraints.BOTH; constraints.weightx = 0.5; constraints.weighty = 0.5; layout.setConstraints(listPanel, constraints); constraints.weightx = 8.0; constraints.weighty = 0.5; layout.setConstraints(tablePanel, constraints); this.setJMenuBar(menuBar); this.add(listPanel); this.add(tablePanel); this.setSize(this.getToolkit().getScreenSize().width * 3 / 4, this .getToolkit().getScreenSize().height * 3 / 4); // 设定窗体的大小 } private void showTime() { int hour = Calendar.getInstance().get(Calendar.HOUR_OF_DAY); int minute = Calendar.getInstance().get(Calendar.MINUTE); int second = Calendar.getInstance().get(Calendar.SECOND); StringBuilder sb = new StringBuilder(); if (hour < 10) { sb.append("0" + hour); } else { sb.append(hour); } if (minute < 10) { sb.append(":0" + minute); } else { sb.append(":" + minute); } if (second < 10) { sb.append(":0" + second); } else sb.append(":" + second); label.setFont(new Font("SansSerif", Font.BOLD, 12)); label.setForeground(Color.BLACK); label.setText(sb.toString()); } class MyTableModel extends AbstractTableModel // 表格模型类，提供表格数据 { private static final long serialVersionUID = 1L; String[] columnName = new String[] // 表格列名 { "Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday" }; @Override public int getColumnCount() // 返回表格列数 { return columnName.length; } public int getRowCount() // 返回表格行数 { return 6; } public String getColumnName(int col) // 获得表格列名 { return columnName[col]; } public Class<? extends Object> getColumnClass(int c) { return getValueAt(0, c).getClass(); } public Object getValueAt(int rowIndex, int columnIndex) { int month = list.getSelectedIndex();// 获得列表的月份 int year = (Integer) spinner.getValue();// 获得spinner显示的年份 GregorianCalendar gc = new GregorianCalendar(year, month, 1); int dayOfWeek = gc.get(Calendar.DAY_OF_WEEK) - 1; // 获得这个月的第一天是星期几 int countDayInMonth = 0;// 某月的总天数，这里的月是从0-11,表示1-12月 if (month == 0 || month == 2 || month == 4 || month == 6 || month == 7 || month == 9 || month == 11) { countDayInMonth = 31; // 是31天的月份 } else if (month == 3 || month == 5 || month == 8 || month == 10) { countDayInMonth = 30; // 是30天的月份 } else if (gc.isLeapYear(year) && month == 1) { countDayInMonth = 29; // 闰年2月 } else if (!gc.isLeapYear(year) && month == 1) { countDayInMonth = 28; // 非闰年2月 } String value = ""; // 因为返回值是Object类型，所以不能直接返回int类型的数据，所以转换成String类型 if (rowIndex == 0) // 第一列的数据 { if (columnIndex < dayOfWeek) { value = ""; } else { value = "" + (columnIndex - dayOfWeek + 1); } } else // 其余列的数据 { if (((rowIndex - 1) * 7) + (columnIndex + 1 + 7 - dayOfWeek) <= countDayInMonth) value = (((rowIndex - 1) * 7) + (columnIndex + 1 + 7 - dayOfWeek)) + ""; } return value; } } @SuppressWarnings("rawtypes") class MyListCellRenderer extends JLabel implements ListCellRenderer // 列表元素绘制类继承自JLabel,实现ListCellRenderer接口 { private static final long serialVersionUID = 1L; public Component getListCellRendererComponent(JList list, // the list Object value, // value to display int index, // cell index boolean isSelected, // is the cell selected boolean cellHasFocus) // does the cell have focus { String s = value.toString().trim(); // 获取选中元素的字符内容 setText(s); // 显示这个字符 Dimension dimension = list.getSize(); // 设定这个每个元素的大小 int height = dimension.height / 12; int width = dimension.width; setSize(width, height); if (isSelected) // 如果该元素被选中，则背景色为红色 { setBackground(Color.red); setForeground(list.getSelectionBackground()); } else // 未被选中的元素背景色显示为灰色，前景色为粉红色 { setBackground(Color.gray); setForeground(Color.pink); } setIcon(new ImageIcon("res\\mon.jpg")); // 设定该元素的图标 setEnabled(list.isEnabled()); setFont(new Font("SansSerif", Font.PLAIN, 20)); // 设定字体大小 setOpaque(true); return this; } } class MyTableRenderer extends JLabel implements TableCellRenderer { private static final long serialVersionUID = 1L; public Component getTableCellRendererComponent(JTable table, Object value, boolean isSelected, boolean hasFocus, int row, int column) { if ((Calendar.getInstance().get(Calendar.DAY_OF_MONTH) + "") // 如果这个标签上的值等于该天的值 .equals(value) && flag == true // 标记为true && list.getSelectedIndex() == Calendar.getInstance().get( Calendar.MONTH) // 列表显示的月份是该月的值 && (Integer) spinner.getValue() == Calendar.getInstance() .get(Calendar.YEAR))// spinner显示的年份是该年 { setFont(new Font("SansSerif", Font.PLAIN, 40)); // 设定字体大小 setText((String) value); // 显示日期字符串 setBorder(UIManager.getBorder("Table.focusCellHighlightBorder")); setForeground(Color.RED); // 设定字符串颜色 flag = false; } else // 如果不是改日的标签上的值 { setFont(new Font("SansSerif", Font.PLAIN, 40)); // 设定字体大小 setText((String) value); // 显示标签上的日期字符串 if (hasFocus) // 如果是被点中的表格的单元格 { setBorder(UIManager .getBorder("Table.focusCellHighlightBorder")); // 设定边框 setForeground(Color.RED);// 设定日期字符串颜色 } else { setForeground(null); setBorder(null); } } return this; } } } ```

Recyclerview嵌套recyclerview的深坑，我坐在Recyclerview这个坑里很久了，仰望天空希望能把我拉上去。

Recyclerview嵌套recyclerview的深坑，对于一个新手来说怎么也上不去，特来邀请键盘中的高手高高手，拉拉我; ## 第一个Recyclerview布局： ``` <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/area_LinearLayout" android:layout_width="match_parent" android:layout_height="match_parent" android:focusable="true" android:focusableInTouchMode="true" android:orientation="vertical"> <LinearLayout android:layout_width="match_parent" android:layout_height="40dp" android:background="@drawable/drawable_black_one" android:orientation="horizontal" android:layout_margin="3dp"> <TextView android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_margin="5dp" android:layout_gravity="center" android:text="" android:textColor="@drawable/drawable_white_pure" android:lines="1" android:layout_weight="1"/> <TextView android:layout_width="1dp" android:layout_height="30dp" android:layout_gravity="center" android:layout_margin="5dp" android:background="@color/whiteness" /> <TextView android:id="@+id/peers_location_TextView" android:layout_width="70dp" android:layout_height="40dp" android:layout_marginLeft="5sp" android:layout_marginRight="10dp" android:ellipsize="end" android:gravity="center" android:text="" android:textColor="@color/whiteness" android:textSize="14sp" android:lines="1" android:textStyle="bold" /> </LinearLayout> <LinearLayout android:layout_width="match_parent" android:layout_height="wrap_content" android:layout_margin="3dp" > <RelativeLayout android:layout_width="wrap_content" android:layout_height="wrap_content" > <ImageView android:layout_width="20dp" android:layout_height="20dp" android:layout_alignParentTop="true" android:layout_alignParentEnd="true" android:layout_marginTop="0dp" android:layout_marginEnd="10dp" android:scaleType="fitStart" android:src="@drawable/location" /> </RelativeLayout> </LinearLayout> <LinearLayout android:layout_width="match_parent" android:layout_height="40dp" android:background="@drawable/drawable_black_one" android:layout_gravity="center" android:focusable="true" android:focusableInTouchMode="true" android:layout_margin="3dp"> <EditText android:layout_width="wrap_content" android:layout_height="match_parent" android:layout_margin="1dp" android:background="@color/text_white" android:hint="行业人员" android:textSize="13dp" android:gravity="center" android:lines="1" android:layout_weight="1"/> <TextView android:layout_width="50dp" android:layout_height="wrap_content" android:text="搜索" android:textSize="14dp" android:layout_marginLeft="14dp" android:layout_gravity="center" android:textColor="@color/whiteness" android:layout_margin="5dp" android:gravity="center"/> </LinearLayout> <android.support.v7.widget.RecyclerView android:id="@+id/user_info_layout" android:layout_width="match_parent" android:layout_height="match_parent" /> </LinearLayout> ``` ## 在第一个Recycleview的item里面嵌套了第二个Recyclerview不知道这样对不对？ ``` <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="match_parent" android:layout_height="wrap_content" android:orientation="vertical"> <LinearLayout android:layout_width="match_parent" android:layout_height="wrap_content"> <LinearLayout android:id="@+id/portrait" android:layout_width="wrap_content" android:layout_height="wrap_content" android:orientation="horizontal"> <ImageView android:id="@+id/user_portrait" android:layout_width="50dp" android:layout_height="50dp" android:layout_margin="5dp" android:src="@drawable/em_default_avatar" /> <LinearLayout android:layout_width="fill_parent" android:layout_height="match_parent" android:layout_weight="1" android:orientation="vertical"> <LinearLayout android:layout_width="match_parent" android:layout_height="20dp" android:layout_marginTop="5dp" android:gravity="clip_horizontal"> <TextView android:id="@+id/user_industry" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_gravity="center" android:background="@drawable/dialog_circular_whiteness" android:ellipsize="end" android:gravity="center" android:text="建筑" android:textColor="@color/colorPrimary" android:textSize="14sp" android:textStyle="bold" /> <TextView android:id="@+id/user_name" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_gravity="bottom" android:layout_marginLeft="5dp" android:background="@drawable/dialog_circular_whiteness" android:ellipsize="end" android:gravity="center" android:text="努力改变自己" android:textColor="#323232" android:textSize="10sp" android:textStyle="bold" /> <TextView android:id="@+id/name_voip" android:layout_width="20dp" android:layout_height="wrap_content" android:layout_gravity="center" android:ellipsize="end" android:gravity="center" android:text="voip" android:textColor="@color/text_pink" android:textSize="7sp" /> </LinearLayout> <LinearLayout android:layout_width="match_parent" android:layout_height="35dp"> <TextView android:layout_width="match_parent" android:layout_height="wrap_content" android:text="努力改变自己" android:textSize="12dp" /> </LinearLayout> </LinearLayout> <RelativeLayout android:layout_width="60dp" android:layout_height="match_parent" android:gravity="center"> <TextView android:id="@+id/user_location" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_marginLeft="20dp" android:background="@drawable/dialog_circular_whiteness" android:text="" android:textSize="12dp" android:textStyle="bold" /> </RelativeLayout> </LinearLayout> </LinearLayout> <LinearLayout android:layout_width="match_parent" android:layout_height="wrap_content" android:orientation="vertical"> <LinearLayout android:layout_width="fill_parent" android:layout_height="match_parent" android:orientation="vertical"> <LinearLayout android:layout_width="match_parent" android:layout_height="wrap_content" android:layout_weight="1"> **<!-- 导入RecyclerView-->** <android.support.v7.widget.RecyclerView android:id="@+id/user_peesr_info" android:layout_width="wrap_content" android:layout_height="wrap_content" /> </LinearLayout> <LinearLayout android:layout_width="fill_parent" android:layout_height="10dp"> <TextView android:layout_width="match_parent" android:layout_height="wrap_content" android:gravity="right" android:text="访问：10000人" android:textSize="8dp" /> </LinearLayout> </LinearLayout> </LinearLayout> ``` ## 第一个Recyclerview的适配器： ``` public class Home_RecyclerView_Adapter extends RecyclerView.Adapter<Home_RecyclerView_Adapter.myViewHodler> { private Context context; private LinkedList<Home_list_get_set> LinkedList; public LinkedList<User_Recruitment_get_set> mLinkedList; public Home_list_get_set mHome_list_get_set; //创建构造函数 public Home_RecyclerView_Adapter(Context context, LinkedList<Home_list_get_set> industrytitlegetsetList) { //将传递过来的数据，赋值给本地变量 this.context = context;//上下文 this.LinkedList = industrytitlegetsetList;//实体类数据ArrayList } /** * 创建viewhodler，相当于listview中getview中的创建view和viewhodler * * @param parent * @param viewType * @return */ @Override public myViewHodler onCreateViewHolder(ViewGroup parent, int viewType) { RecyclerView user_peesr_info;//自定义recyclerveiw的适配器 //创建自定义布局 // View itemView = View.inflate(context, R.layout.peers_list_item, null);//用这个布局item宽高无效 // myViewHodler itemView = new myViewHodler(LayoutInflater.from(context).inflate(R.layout.peers_list_item, parent, false)); View view = LayoutInflater.from(parent.getContext()).inflate(R.layout.peers_list_item, parent, false); user_peesr_info = view.findViewById (R.id.user_peesr_info); //给嵌套的RecyclerView设置适配器 User_Recruitment_Adapter user_recruitment_adapter = new User_Recruitment_Adapter (context,mLinkedList); user_peesr_info.setAdapter (user_recruitment_adapter); user_peesr_info.setLayoutManager (new LinearLayoutManager (context, LinearLayoutManager.HORIZONTAL, false)); //给嵌套的RecyclerView设置item的分割线 user_peesr_info.addItemDecoration (new DividerItemDecoration (context, DividerItemDecoration.HORIZONTAL)); return new myViewHodler(view); // return itemView; } /** * 绑定数据，数据与view绑定 * * @param holder * @param position */ @SuppressLint("ClickableViewAccessibility") @Override public void onBindViewHolder(myViewHodler holder, int position) { //根据点击位置绑定数据 mHome_list_get_set = LinkedList.get(position); // holder.mItemGoodsImg; holder.user_name.setText(mHome_list_get_set.getUser_name()); holder.user_industry.setText(mHome_list_get_set.getUser_work()); // holder.user_portrait.setImageDrawable (data.getHead_portait ());//改为下面Glide获取图上 Glide.with(context) .load(mHome_list_get_set.getHead_portait ())//图片信息 .apply(RequestOptions.bitmapTransform(new CircleCrop ()))//设置圆形 .into(holder.user_portrait);//设置到那个部位 holder.name_voip.setText(mHome_list_get_set.getUser_Vip()); holder.user_location.setText(mHome_list_get_set.getUser_location()); } /** * 得到总条数 * * @return */ @Override public int getItemCount() { // return LinkedList.size(); return LinkedList == null ? 0 : LinkedList.size(); } //自定义viewhodler class myViewHodler extends RecyclerView.ViewHolder { private ImageView user_portrait; private TextView user_name; private TextView user_industry; private TextView name_voip; private TextView user_location; public RecyclerView user_peesr_info;//自定义recyclerveiw的适配器 public myViewHodler(View itemView) { super(itemView); user_peesr_info = itemView.findViewById (R.id.user_peesr_info); user_portrait = itemView.findViewById(R.id.user_portrait); user_name = itemView.findViewById(R.id.user_name); user_industry = itemView.findViewById(R.id.user_industry); name_voip = itemView.findViewById(R.id.name_voip); user_location = itemView.findViewById(R.id.user_location); user_portrait.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { //可以选择直接在本位置直接写业务处理 //Toast.makeText(context,"点击了xxx",Toast.LENGTH_SHORT).show(); //此处回传点击监听事件 if (onItemClickListener != null) { onItemClickListener.OnItemClick(v, LinkedList.get(getLayoutPosition())); } } }); } public View getItemView() { return itemView; } } /** * 设置item的监听事件的接口 */ public interface OnItemClickListener { /** * 接口中的点击每一项的实现方法 * * @param view 点击的item的视图 * @param data 点击的item的数据 */ public void OnItemClick(View view, Home_list_get_set data); } //需要外部访问，所以需要设置set方法，方便调用 private OnItemClickListener onItemClickListener; public void setOnItemClickListener(OnItemClickListener onItemClickListener) { this.onItemClickListener = onItemClickListener; } ``` ## 第二个Recyclerview的适配器： ``` public class User_Recruitment_Adapter extends RecyclerView.Adapter<User_Recruitment_Adapter.myViewHodler> { public LinkedList<User_Recruitment_get_set> m_LinkedList; private Context context; public User_Recruitment_get_set mUser_Recruitment_get_set; //创建构造函数 public User_Recruitment_Adapter(Context context, LinkedList<User_Recruitment_get_set> mLinkedList) { //将传递过来的数据，赋值给本地变量 this.context = context;//上下文 this.m_LinkedList = mLinkedList; } @NonNull @Override public myViewHodler onCreateViewHolder(@NonNull ViewGroup viewGroup, int i) { View view = LayoutInflater.from(viewGroup.getContext()).inflate(R.layout.user_peers_recruitment_item, viewGroup, false); return new myViewHodler(view); } @Override public void onBindViewHolder(@NonNull myViewHodler myViewHodler, int i) { mUser_Recruitment_get_set = m_LinkedList.get(i); myViewHodler.recruitment.setText (mUser_Recruitment_get_set.getRecruitment ()); } @Override public int getItemCount() { return m_LinkedList == null ? 0 : m_LinkedList.size(); } public class myViewHodler extends RecyclerView.ViewHolder { private TextView recruitment; public myViewHodler(@NonNull View itemView) { super (itemView); recruitment = itemView.findViewById(R.id.recruitment); } } } ``` ## 现问题是嵌套里面的Recyclerview无显示内容？我该如何写？

关于java的聊天程序,分服务端和客户端，请java大神帮我调试一下,我检查没编写错误

//服务端 package chatApp; import java.net.*; import java.io.*; import java.util.*; public class chatserverthree implements Runnable { public static final int PORT=1234; protected ServerSocket listen; static Vector connections; Thread connect; public chatserverthree() { try { listen=new ServerSocket(PORT); } catch(UnknownHostException e2) { System.err.println("erro:"+e2); } catch(IOException e) { System.err.println("erro:"+e); System.exit(1); } connections=new Vector(1000); connect=new Thread(this); connect.start(); } public static void main(String args[]) { new chatserverthree(); System.out.println("Chat Server is starting!......"); } public void run() { try { while(true) { Socket client=listen.accept(); firstthread f=new firstthread(this,client); f.setPriority(Thread.MIN_PRIORITY); f.start(); connections.addElement(f); } } catch(IOException e) { System.err.println("Erro:"+e); System.exit(1); } } public void broadcast(String msg) { int i; firstthread you; for(i=0;i<connections.size();i++) { you=(firstthread)connections.elementAt(i); try { you.out.writeUTF(msg); } catch(IOException e){} } } public void broadcast1(String msg) { int i; String s1,s2,s3; firstthread you; s1=new String("PEOPLE"); s2=new String(msg.substring(4)); s3=s1.concat(s2); for(i=0;i<connections.size();i++) { you=(firstthread)connections.elementAt(i); if(s3.startsWith(you.name)) { try { you.out.writeUTF(msg); } catch(IOException e){} } } } } class firstthread extends Thread { protected Socket client; String line,name; protected DataOutputStream firstout,out; protected chatserverthree server; protected DataInputStream in; public firstthread(chatserverthree server,Socket client) { this.server=server; this.client=client; try { in=new DataInputStream(client.getInputStream()); out=new DataOutputStream(client.getOutputStream()); firstout=new DataOutputStream(client.getOutputStream()); } catch(IOException e) { try { server.connections.removeElement(this); client.close(); } catch(IOException e2) { System.err.println("有问题哦："+e); return; } } if(this.client==null) { server.broadcast("QUIT"+this.name); this.name=null; } } public void run() { try { for(int i=0;i<server.connections.size();i++) { firstthread c=(firstthread)(server.connections.elementAt(i)); if(c.name!=null) { try { firstout.writeUTF(c.name+"*"); } catch(IOException e){} } } } catch(ArrayIndexOutOfBoundsException e){} catch(NullPointerException e){} try { while(true) { line=in.readUTF(); if(line.startsWith("PEOPLE")) { try { firstthread d=(firstthread)(server.connections.elementAt (server.connections.indexOf(this))); if(d.name==null) { d.name=line; } else if(d.name!=null) { server.broadcast("QUIT"+this.name); d.name=line; } } catch(ArrayIndexOutOfBoundsException e){} catch(NullPointerException e){} finally { server.broadcast(line); } } else if(line.startsWith("QUIT")) { server.broadcast("QUIT"+this.name); server.connections.removeElement(this); this.in.close(); this.out.close(); this.firstout.close(); this.client.close(); this.yield(); } else if(line.startsWith("MSG")) { server.broadcast(line); } else if(line.startsWith("悄悄地对")) { this.out.writeUTF(line); 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