无法将数据(类型接口{})转换为类型 string: need 类型断言

Question

I am pretty new to go and I was playing with this notify package.

At first I had code that looked like this:

func doit(w http.ResponseWriter, r *http.Request) {
    notify.Post("my_event", "Hello World!")
    fmt.Fprint(w, "+OK")
}

I wanted to append newline to Hello World! but not in the function doit above, because that would be pretty trivial, but in the handler afterwards like this below:

func handler(w http.ResponseWriter, r *http.Request) {
    myEventChan := make(chan interface{})
    notify.Start("my_event", myEventChan)
    data := <-myEventChan
    fmt.Fprint(w, data + "\n")
}

After go run:

$ go run lp.go 
# command-line-arguments
./lp.go:15: invalid operation: data + "\n" (mismatched types interface {} and string)

After a little bit of Googling I found this question on SO.

Then I updated my code to:

func handler(w http.ResponseWriter, r *http.Request) {
    myEventChan := make(chan interface{})
    notify.Start("my_event", myEventChan)
    data := <-myEventChan
    s:= data.(string) + "\n"
    fmt.Fprint(w, s)
}

Is this what I was supposed to do? My compiler errors are gone so I guess that's pretty good? Is this efficient? Should you do it differently?

转载于:https://stackoverflow.com/questions/14289256/cannot-convert-data-type-interface-to-type-string-need-type-assertion

Answer 1

According to the Go specification:

For an expression x of interface type and a type T, the primary expression x.(T) asserts that x is not nil and that the value stored in x is of type T.

A "type assertion" allows you to declare an interface value contains a certain concrete type or that its concrete type satisfies another interface.

In your example, you were asserting data (type interface{}) has the concrete type string. If you are wrong, the program will panic at runtime. You do not need to worry about efficiency, checking just requires comparing two pointer values.

If you were unsure if it was a string or not, you could test using the two return syntax.

str, ok := data.(string)

If data is not a string, ok will be false. It is then common to wrap such a statement into an if statement like so:

if str, ok := data.(string); ok {
    /* act on str */
} else {
    /* not string */
}