如何在C++中用重载让两个数组相加？

Question

这是我写的代码，没有错误但是没有结果。请大佬给我看一下，谢谢！
#include
#include
#include
using namespace std;
class Myclass
{
public:
int x = 0, y = 0;
Myclass() {}
void array()
{
int i = 0, j = 0;
do
{
cin >> a[i][j]; j++; y = j;
if (j % 3 == 0) { i++; x = i; }
} while (a[i][j] != EOF);
}
Myclass(int i, int j)
{
srand(int(time(0)));
for (int o = 0; o < i; o++)
{
for (int p = 0; p < j; p++)
b[o][p] = rand() % +100;
}
}
Myclass operator+(Myclass&none)
{
Myclass in;
for (int i = 0; i < x; i++)
{
for (int j = 0; j < y; j++)
{
in.c[i][j] = a[i][j] + b[i][j];
}
}
return in;
}
void show()
{
for (int p = 0; p < x; p++)
{
for (int o = 0; o < y; o++)
{
cout << c[p][o];
}
cout << endl;
}
}
private:
int a[20][20], b[20][20], c[20][20];
};
int main()
{
Myclass one;
cout << "please input one array:" << endl;
one.array(); Myclass two(one.x, one.y);
Myclass three; three = one + two; three.show();
return 0;
}

Answer 1

array函数中把do-while循环改成while循环，并且把循环条件改成cin>>a[i][j]，把循环体中的cin语句去掉。因为cin不能读入EOF。

现在看来应该是x和y有问题（我让程序输出了one.x和one.y）：
please input one array:
1 2 3 4 5 6 7 8 9 10 11 -12 -13 20 21 t //以非整数为读入数据的结束
(69,208)