各位大大 来帮我看下这段html
最外面只有一个DIV层 网页布局没用表格
我想取type subtype 等标签所对应的内容 比如 type对应内容Bars,Clubs,Restaurants ,Sub Type对应内容African 这些内容都写在标签之外 正则会的不多 想不到很好的能取到所有内容 并能让内容一一对应的方法 有解决办法吗?刚学ruby不久实在想不出方法
<legend>Venue Details</legend> <img width="150" align="right" src="/userimages/Afrodisiac-_-Voodoo-Lounge.jpg"/> <strong>Type - </strong> Bars, Clubs, Restaurants <br/><br /> <strong>Sub Type - </strong> African <br /><br /> <strong>Ambiance - </strong> Look your best <br/><br /> <strong>Address</strong><br /> Cnr Civin Dr and Linksfield Dr, Linksfield, Johannesburg <br/><br/> <strong>Phone</strong><br /> 011 443 9990 <br/><br/> <strong>Phone</strong><br /> 082 218 3698 <br/><br/> <strong>Email</strong><br /> <a href="mailto:info@theafrodisiac.co.za">info@theafrodisiac.co.za</a><br/><br/> <strong>Web</strong><br /> <a href="http://www.theafrodisiac.co.za" target="_blank">http://www.theafrodisiac.co.za</a><br/><br/> <strong>Venue info</strong><br/><br/> This grillhouse just off the N3 at Linksfield also offers traditional African cuisine, a unique experience. The venue plays host to party nights featuring top DJs.<br/> <strong>For future easy access</strong><br /> <a href="http://www.jhblive.com/afrodisiac" target="_blank">http://www.jhblive.com/afrodisiac</a><br/><br/>