python加密文件读取

Question

Answer 1

s=input()
zimu="abcdefghijklmnopqrstuvwxyz"
zimu=zimu[::-1]#逆序
t=[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,]
with open('encrypt.txt','r')as f:
    data = f.read()
s1=""
res=""
l= len(s)
for i in range(l):#去重
    if(s[i]>='a' and s[i]<='z'):
        if t[ord(s[i])-ord('a')]==0:
            s1=s1+s[i]
            t[ord(s[i])-ord('a')]=1
        else:
            continue
 
#print(data[ord(data[0])-ord('a')])
for i in range(26):
    if t[ord(zimu[i])-ord('a')]==0:
        s1=s1+zimu[i]
        t[ord(zimu[i]) - ord('a')] =1
 
l= len(data)
for i in range(l):#加密
    if(data[i]>='a' and data[i]<='z'):
        res=res+s1[ord(data[i])-ord('a')]
    else:
        res = res + data[i]
with open('output.txt','w')as f:
    f.write(res)

首先是去重操作，先选一个字母，然后把该字母后面的相同的元素全部变为0，之后在遍历一遍，输出非零字母。然后是反序追加，在去重数组里出现过的字母就不追加，否则就追加，追加完成后变成加密数组。最后是加密，通过加密数组实现就行了。