C++在N1到N2中找出同时满足用3除余2

Question

 

Answer 1

#include <stdio.h>
int main()
{
    int i,N1,N2,sum=0;
    scanf("%d %d",&N1,&N2);
    for(i=N1;i<=N2;i++){
        if(i%3==2&&i%5==3&&i%7==2){
            sum+=i;
        }
    }
    printf("%d",sum);
    return 0;
}