用Python随机生成100以内10×10的随机整数矩阵

Question

 

Answer 1

import random

li = []

for i in range(10):

    li.append([random.randint(1,100) for j in range(10)])

print(*li,sep='\n')

Answer 2

#!/usr/bin/python
# -*- coding: UTF-8 -*-
"""
@author: YangPC
@time:2021/06/17
@QQ:327844761
@微信公众号：ewbang
"""

import random


def fun():
    lists = []
    for i in range(10):
        lists.append([random.randint(1, 100) for j in range(10)])
    with open('rm.txt', 'a') as f1:
        for line in lists:
            f1.write(' '.join(str(i) for i in line) + "\n")
    with open('rm.txt', 'r') as f2:
        for line in f2.readlines():
            newLine = ','.join(line.split(' '))
            with open('rm.csv', 'a') as f3:
                f3.write(newLine)


if __name__ == '__main__':
    fun()

程序输出截图：

编码不易，望采纳！ 

Answer 3

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