整不会了，整不会了，快来看看

Question

Answer 1

#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
int i,n;
double x, zi, mu=1, t, sum=1;
printf("请输入x和n的值：");
scanf("%lf,%d", &x, &n);
for (i = 1; i <= n; i++)
{
zi = pow(x, i);
t = zi / mu;
sum = sum + t;
mu = mu * (i + 1);
}
printf("sum=%f", sum);
return 0;
}