关于字典融合为列表的问题

Question

dic = {'0':[0,1,2,3],'1':[25,23,24,25,26,27,252,5],'2':[102,198]}
如何最简单的方法实现使 dic 的value 拿出第索引个值，组成列表，如下：
[0,25,102] , [1,23,198], [2,24,None],[3,25,None],[None,26,None],[None,27,None],[None,252,None],[None,5,None]
如何实现此想法

Answer 1

import itertools as mi

dic = {'0':[0,1,2,3],
       '1':[25,23,24,25,26,27,252,5],
       '2':[102,198]}

print(list(mi.zip_longest(*dic.values())))