需要零花钱的朋友看过来啦，5元1道python练习题（共4道），只需要做出来就可以了

Question

问题遇到的现象和发生背景

Given an array of integers $A[0..n-1]$ and $m$ queries $b_j$.For each query report is th number $b_j$ is one of elements in $A$.InputThe first input line contains integer $n$ ($1 \le n \le 500$).
Next line contains $n$ integer numbers $A[0..n-1]$ ($0 \le A[i] \le 1000$).The third line contains integer $m$ ($1 \le m \le 500$).
Each of next $m$ lines contains query $b_j$.OutputFor each query output FOUND if required number is in array or MISSED otherwise

输入输出

standard input
5
1 2 3 4 5
5
1
2
6
0
5
standard output
FOUND
FOUND
MISSED
MISSED
FOUND

standard input
5
1 2 1 2 1
5
1
2
1
2
3
standard output
FOUND
FOUND
FOUND
FOUND
MISSED

Answer 1

No1.

len_as = input()
len_a = int(len_as)
str_a = input()
a = str_a.split(' ')

len_bs = input()
len_b = int(len_bs)
arr_b = []
for i in range(len_b):
    str_b = input()
    arr_b.append(str_b)

for i in arr_b:
    if i in a:
        print("FOUND")
    else:
        print("MISSED")

5
1 2 3 4 5
5
1
2
4
5
7
FOUND
FOUND
FOUND
FOUND
MISSED

No2.

len_as = input()
str_a = input()
a = str_a.split(' ')

len_bs = input()
str_b = input()
b = str_b.split(' ')

a.extend(b)
for i in a:
    print(i, end=' ')

1
5
3
1 2 3
5 1 2 3