输入奇数 产出奇数阶的幻方，但是我的程序运行之后总是出错 望大家解答一下

Question

#include <stdio.h>
int main(void)
{
int m,l,p,n,i,j;
printf("This program creates a magic square of a specified size.\n");
printf("The size must be an odd number between 1 and 99.\n");
printf("Enter size of magic square: ");
scanf("%d",&n);
int a[n][n];
for (i=0;i<n;i++){
for (j=0;j<n;j++)
a[i][j]=0;
}
l=n / 2;
a[0][l]=1;
m=n * n;
for (i=n-1;1;i--){
if (i==-1)
i=n - 1;
for (j=l+1;1;j++){
if (j==n)
j=0;
for (p=2;p<=m;p++){
if (a[i][j]==0){
a[i][j]=p;
}
else{
i=i + 2;
j=j - 1;
a[i][j]=p;
}
}
}
}
for (i=0;i<n;i++){
for (j=0;j<=n;j++){
if (j==n)
printf("\n");
else
printf("%d",a[i][j]);
}
}
return 0;
}

Answer 1

帮你找个能用的，自己对比着看看

#include <stdio.h>
int main()
{
    int i,j, n, k = 1;
    scanf("%d", &n);
    int a[n][n];
    for (i = 0; i < n; i++)
        for (j = 0; j < n; j++)
            a[i][j] = 0;
    a[i = 0][j = n / 2] = k;
    for (k = 2; k <= n * n; k++)
    {
        i -= 1;
        j += 1;
        if (i == -1 && j != n)
        {
            i = n - 1;
            a[i][j] = k;
        }
        else if (j == n && i != -1)
        {
            j = 0;
            a[i][j] = k;
        }
        else if ((i == -1 && j == n) || a[i][j] != 0)
        {
            i += 2;
            j -= 1;
            a[i][j] = k;
        }
        else
            a[i][j] = k;
    }
    
    for (i = 0; i < n; i++)
    {
        for (j = 0; j < n; j++)
            printf("%3d", a[i][j]);
        printf("\n");
    }
    printf("\n");
    return 0;
}