简单函数数组，高采纳率

Question

#include<stdio.h>
int main()
{
float m(float a[ ],int n);
float zu1[5],zu2[5];
int i,n;
for(i=0;i<5;i++)
scanf("%f",&zu1[i]);
for(i=0;i<5;i++)
scanf("%f",&zu2[i]);
printf("%f\n",m(zu1,5));
printf("%f\n",m(zu2,5));
return 0;
}
float m(float a[ ],int n)
{
float sum=a[0],i,pjs;
for(i=1;i<n;i++)
{
sum=sum+a[i];
}
pjs=sum/n;
return(pjs);

}
报array subacript is not an integer

Answer 1

数组下标只接受int 你把i分开定义成int