左左才 2021-12-14 23:25 采纳率: 100%
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DB2使用with子查询的时候,添加where条件无法进行除法运算

DB2使用with子查询的时候,添加where条件无法进行除法运算,
刚开始:

WITH
T1 AS (SELECT * FROM Track T LEFT JOIN Customer C on  C.CustomerId =T.TrackId WHERE T.UnitPrice =0.99 and T.Bytes >500000),
T2 AS (SELECT SUM(Bytes)/COUNT(Name) FROM T1),
T3 AS (SELECT COUNT(Name) num_one FROM T1),
T4 AS (SELECT COUNT(*) AS number_two FROM T1 WHERE Bytes <(SELECT * FROM T2)),
demo_a as(SELECT ((SELECT * FROM T4)+(SELECT * FROM T3))AS addition),
demo_b as(SELECT ((SELECT * FROM T4)-(SELECT * FROM T3))AS subtraction),
demo_c as(SELECT ((SELECT * FROM T4)*(SELECT * FROM T3))AS multiplication),
demo_d as(SELECT ((SELECT * FROM T4)/(SELECT * FROM T3))AS division)
SELECT * FROM T3,T4,demo_a,demo_b,demo_c,demo_d;

数据库返回:

num_one|number_two|addition|subtraction|multiplication|division|
-------+----------+--------+-----------+--------------+--------+
   3284|      1880|    5164|      -1404|       6173920|       0|

简化SQL后:

WITH 
T1 AS (SELECT COUNT(FirstName) NUMBER_ONE FROM Customer),
T2 AS (SELECT SUM (CustomerId) NUMBER_TWO FROM Customer WHERE CustomerId=9),
DEMO_A AS (SELECT((SELECT * FROM T2)/(SELECT * FROM T1))AS DIVISION)
SELECT * FROM T2,T1,DEMO_A

SQL还是无法相除:

NUMBER_TWO|NUMBER_ONE|DIVISION|
----------+----------+--------+
         9|        59|       0|

第三次手残简化,去除where条件,竟然成功了:

WITH 
T1 AS (SELECT COUNT(FirstName) NUMBER_ONE FROM Customer),
T2 AS (SELECT SUM (CustomerId) NUMBER_TWO FROM Customer),
DEMO_A AS (SELECT((SELECT * FROM T2)/(SELECT * FROM T1))AS DIVISION)
SELECT * FROM T2,T1,DEMO_A
NUMBER_TWO|NUMBER_ONE|DIVISION|
----------+----------+--------+
      1770|        59|      30|
  • 写回答

2条回答 默认 最新

  • DarkAthena ORACLE应用及数据库设计方案咨询师 2021-12-15 13:55
    关注

    9除以59的结果是小于1的,你看下是不是显示做了格式化,只保留了整数显示,尝试把显示改成多保留几位小数

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
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  • 系统已结题 12月23日
  • 已采纳回答 12月15日
  • 创建了问题 12月14日

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