学生链表的构造与输出

Question

问题遇到的现象和发生背景

学生链表的构造与输出

问题相关代码，请勿粘贴截图

运行结果及报错内容

我的解答思路和尝试过的方法

我想要达到的结果

#include  <iostream>
#include  <iomanip>
using  namespace  std;

struct  Student{
        long  number;
        float  score;
        Student*  next;
};

;  //  定义头节点

Student*  getNode(){
        int  num;
        float  sc;
        cin  >>  num  >>  sc;
        if(num  ==  0)  {
                return  NULL;
        }
        Student*  p  =  new  Student;
        p->number  =  num;
        p->score  =  sc;
        p->next  =  0;
        return  p;
}

void  Create()  {
        if((head  =  getNode())  ==  0)  {    //  添加结束条件
                
break;
;
        }
        for  (       )  {    //  循环添加
                pE->next  =  pS;
        }
}

void  ShowList()  {
        cout  <<  "now  the  itens  of  list  are  \n";
        for(         )  {    //  循环输出
                cout<<  p->number  <<  ","  <<  p->score  <<  endl;
        }
}

int  main(){
        cout  <<  fixed  <<  setprecision(1);
        Create();
        ShowList();
}

Answer 1

#include <iostream>
#include <iomanip>

using namespace std;

struct Student
{
    long number;
    float score;
    Student *next;
};

Student *head; //  定义头节点

Student *getNode()
{
    int num;
    float sc;
    cin >> num >> sc;
    if (num == 0)
    {
        return NULL;
    }
    Student *p = new Student;
    p->number = num;
    p->score = sc;
    p->next = 0;
    return p;
}

void Create()
{
    if ((head = getNode()) == 0)
    { //  添加结束条件
        return;
    }

    for (Student *pE = head, *pS = getNode(); pS; pE = pS, pS = getNode())
    { //  循环添加
        pE->next = pS;
    }
}

void ShowList()
{
    cout << "now  the  itens  of  list  are  \n";
    for (Student *p = head; p; p = p->next)
    { //  循环输出
        cout << p->number << "," << p->score << endl;
    }
}

int main()
{
    cout << fixed << setprecision(1);
    Create();
    ShowList();
}