输入n后回车出现一个0

Question

#include<stdio.h>
#include<string.h>

 
int main()
{
    char a[10];
    int n,j;
    scanf("%d",&n);
    while(n--)
    {
     gets(a);
     int i,h=0;
     for(i=0 ; a[i]!='\0' ; i ++)
     {
         if(a[i] == 'I')h =h+1;
         if(a[i] == 'V')h=h+5;
         if(a[i] == 'X')h =h+10;
         if(a[i] == 'L')h =h+50;
         if(a[i] == 'C')h =h+100;
         if(a[i] == 'D')h =h+ 500;
         if(a[i] == 'M')h =h+ 1000;
     }
     if(strstr(a,"IV"))h =h-2;
     if(strstr(a,"IX"))h =h-2;
     if(strstr(a,"XL"))h =h-20;
     if(strstr(a,"XC"))h =h-20;
     if(strstr(a,"CD"))h =h-200;
     if(strstr(a,"CM"))h =h-200;
     printf("%d\n",h);
    }
     return 0;
}

Answer 1

因为你输入n的值3后，按回车键了。这样gets(a)实际自动接收了换行符，不需要你再输入内容。这样导致a字符串是个空串，最后h没有赋予任何值，还是初始的0，所以输出了0
修改办法： scanf("%d",&n);后增加一句getchar();就可以了，把换行符接收掉