为什么会出现科学计数法的形式？

Question

/*编写重载函数可分别求取
两个整数，三个整數，两个双精度数，三个双精度数的最大值。
并在主函数中分别测试。*/
#include <iostream>

using namespace std;
    int Max1(int,int);
    int Max1(int,int,int);
    double Max1(double,double);
    double Max1(double,double,double);

//此处添加用户自定义的函数代码

int main()
{
    int x1,x2;
    cin>>x1>>x2;
    cout<<Max1(x1,x2);
    int x3,x4,x5;
    cin>>x3>>x4>>x5;
    cout<<Max1(x3,x4,x5);
    double x6,x7;
    cin>>x6>>x7;
    cout<<Max1(x6,x7);
    double x8,x9,x0;
    cin>>x8>>x9>>x0;
    cout<<Max1(x8,x9,x0);

    //此处添加代码
    return 0;
}
int Max1(int a,int b)
{
    return a>b?a:b;
}
int Max1(int a,int b,int c)
{
    int Max1=a>b?a:b;
    return Max1>c?Max1:c;
}
double Max1(double a,double b)
{
    return a>b?a:b;
}
double Max1(double a,double b,double c)
{
    double Max1=a>b?a:b;
    return Max1>c?Max1:c;
}

输入 1 2 3 1.1 2.2 3.3
理想输出 2 3 2.2 3.3

Answer 1

//输入太多了，已改好，希望对你有用，望采纳
#include <iostream>
 
using namespace std;
    int Max1(int,int);
    int Max1(int,int,int);
    double Max1(double,double);
    double Max1(double,double,double);
 
//此处添加用户自定义的函数代码
 
int main()
{
    int x1,x2;
    cin>>x1>>x2;
    cout<<Max1(x1,x2);
    int x3;
    cin>>x3;
    cout<<Max1(x1,x2,x3);
    double x6,x7;
    cin>>x6>>x7;
    cout<<Max1(x6,x7);
    double x8;
    cin>>x8;
    cout<<Max1(x6,x7,x8);
 
    //此处添加代码
    return 0;
}
int Max1(int a,int b)
{
    return a>b?a:b;
}
int Max1(int a,int b,int c)
{
    int Max1=a>b?a:b;
    return Max1>c?Max1:c;
}
double Max1(double a,double b)
{
    return a>b?a:b;
}
double Max1(double a,double b,double c)
{
    double Max1=a>b?a:b;
    return Max1>c?Max1:c;
}