页面上有四个表单,提交的时候把数据分别封装到4个对象里,怎么通过ajax返回这四个对象,并且在后台接收呢。页面用的是miniui,后台用的hibernate
这是 我前端接收并封装四个表单数据到四个json对象里的代码
mini.parse();
var tableDiv1 = new mini.Form("#tableDiv1");
var tableDiv2 = new mini.Form("#tableDiv2");
var tableDiv3 = new mini.Form("#tableDiv3");
var tableDiv4 = new mini.Form("#tableDiv4");
function saveLocal() {
var data1 = tableDiv1.getData();
tableDiv1.validate();
if (tableDiv1.isValid() == false) return
var data2 = tableDiv2.getData();
tableDiv2.validate();
if (tableDiv2.isValid() == false) return;
var data3 = tableDiv3.getData();
tableDiv3.validate();
if (tableDiv3.isValid() == false) return;
var data4 = tableDiv4.getData();
tableDiv4.validate();
if (tableDiv4.isValid() == false) return;
var json1 = mini.encode(data1); //序列化成JSON格式字符串
let inspectionRecord = JSON.parse(json1); //JSON格式字符串转为json对象
var json2 = mini.encode(data2);
let checkItemInformation = JSON.parse(json2);
var json3 = mini.encode(data3);
let checkSpecimenInformation = JSON.parse(json3);
var json4 = mini.encode(data4);
let checkImageInformation = JSON.parse(json4);
var jsonStr = {inspectionRecord:inspectionRecord , checkItemInformation:checkItemInformation,checkSpecimenInformation:checkSpecimenInformation,checkImageInformation:checkImageInformation};
console.info([{inspectionRecord} , {checkItemInformation},{checkSpecimenInformation},{checkImageInformation}]);
$.ajax({
url: "${ctx}/ClinicalInspectionReportRecord/SaveLocalReportRecord",
cache: false,
type: "post",
contentType: "application/json;charset=utf-8",
data: JSON.stringify({"allBean":jsonStr}),
success: function (text) {
if ('200'==text.returnCode) {
mini.alert(text.returnMsg,"提示",window.CloseOwnerWindow);
} else {
mini.alert(text.returnMsg);
}
},
error: function (jqXHR, textStatus, errorThrown) {
mini.alert(jqXHR.responseText);
CloseWindow();
}
});
}
运行结果及报错内容
我想要达到的结果