用c++显示学生成绩

Question

用c++表示学生的输出成绩，≥90为优秀，80到89为良，70到79为中，60到69为及格，60之下为不及格

Answer 1

#include "stdafx.h"
#include<iostream>
using namespace std;
void main()
{
int score;
cout << "请输入成绩：" << endl;
cin >> score;
if (score > 100)
cout << "成绩输入有误，重新输入！" << endl;
else if (score >= 90 && score <= 100)
cout << "成绩等级为：优秀" << endl;
else if (score >= 80 && score < 90)
cout << "成绩等级为：良" << endl;
else if (score >= 70 && score <80)
cout << "成绩等级为：中" << endl;
else if (score >= 60 && score < 70)
cout << "成绩等级为：及格" << endl;
else
cout << "成绩等级为：不及格" << endl;
}

感谢采纳！