这个是怎么回事呢求解析过程

Question

,下列程序的输出结果
#include <stdio.h>
struct abc
｛
int a, b, с;
｝；
void main()
｛
struct abc

s[2]=｛｛1,2,3｝，｛4,5,6｝｝
int t;

t=s[0].a+s[1].b;

printf("%d\n",t);
}

Answer 1

6
s[0].a = 1
s[1].b = 5

注：s[0]的a，b，c分别为1,2,3；s[1]的a，b，c分别为4,5,6

---

#include <stdio.h>
struct abc
{
    int a, b, с;
};
int main()
{
    struct abc s[2]={{1,2,3},{4,5,6}};
    int t;
    t=s[0].a+s[1].b;
    
    printf("%d\n",t);
}