SyntaxError: invalid syntax print "get remote configure failed: %s, %s" %

Question

 Python  3.9
 print "get remote configure failed: %s, %s" % (REMOTE_JSON_FILE, e.message) 

SyntaxError: invalid syntax

def GetClangConfigFromRemote():
    global g_clang_format_config
    res = None
    try:
        res = urllib.request.urlopen(REMOTE_JSON_FILE, timeout=3.0)
    except Exception as e:
        print "get remote configure failed: %s, %s" % (REMOTE_JSON_FILE, e.message)
        print "use local default config instead"
        g_clang_format_config = DEFAULT_CONFIG
        return True

    jsonDict = None
    try:
        jsonDict = json.loads(res.read())
    except Exception as e:
        print "parse json failed:%s" % e.message
        print "use local default config instead"
        g_clang_format_config = DEFAULT_CONFIG
        return True
    g_clang_format_config = jsonDict["C_Cpp.clang_format_style"]
    return True

运行结果及报错内容

print "get remote configure failed: %s, %s" % (REMOTE_JSON_FILE, e.message)
^
SyntaxError: invalid syntax

Answer 1

print是函数，加括号

def GetClangConfigFromRemote():
    global g_clang_format_config
    res = None
    try:
        res = urllib.request.urlopen(REMOTE_JSON_FILE, timeout=3.0)
    except Exception as e:
        print ("get remote configure failed: %s, %s" % (REMOTE_JSON_FILE, e.message))
        print ("use local default config instead")
        g_clang_format_config = DEFAULT_CONFIG
        return True
 
    jsonDict = None
    try:
        jsonDict = json.loads(res.read())
    except Exception as e:
        print ("parse json failed:%s" % e.message)
        print ("use local default config instead")
        g_clang_format_config = DEFAULT_CONFIG
        return True
    g_clang_format_config = jsonDict["C_Cpp.clang_format_style"]
    return True