如何从在json中发送响应的URL读取响应

Question

I have been given an API url feed which returns response in JSON format and I have been told to set the headers to this:

Accept: application/json
X-some-API-Key: fdfdfdfdsgddc43aa96c556eb457b4009

Could anyone please tell me how to move ahead with this problem?

Answer 1

Question 1

I would use the PHP curl libraries.

For example:

// create a new cURL resource
$ch = curl_init();

// set URL and other appropriate options
curl_setopt($ch, CURLOPT_URL, "http://www.example.com/");
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_HTTPHEADER, array(
    'Accept: application/json', 
    'X-some-API-Key: fdfdfdfdsgddc43aa96c556eb457b4009',
));

// grab URL and pass it to the browser
echo curl_exec($ch);

// close cURL resource, and free up system resources
curl_close($ch);

See curl_setopt() for more information on the constants such as CURLOPT_HTTPHEADER I have used above.

Question 2 from comments

// create a new cURL resource
$ch = curl_init();

// set URL and other appropriate options
curl_setopt($ch, CURLOPT_URL, "http://www.example.com/");
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_HTTPHEADER, array(
    'Accept: application/json', 
    'X-some-API-Key: fdfdfdfdsgddc43aa96c556eb457b4009',
));

// grab URL and pass it to the browser
$json = json_decode(curl_exec($ch), true);

// close cURL resource, and free up system resources
curl_close($ch);

$json now contains an associative array of the response, which you can var_dump()to see the structure.