使用jQuery发布屏幕宽度

Question

Using this code

var sw = window.screen.width;
$.post("http://www.example.com/track.php", {result: sw
}, "html");

and $_SERVER['result']; in the server I'm trying to get the sreen width but it does not work. It is something wrong with the "result". I'm new in Javascript and jQuery...

http://api.jquery.com/jQuery.post/

Answer 1

$_SERVER contains server variables, that is, things like the operating system, the referrer URL, paths to various folders on the server.

What you're looking for instead is either the $_POST array, the $_GET array, or the $_REQUEST array. I might be stating the obvious here, but here's what they contain:

• $_POST contains a list of all variables POSTed to the script.
• $_GET contains a list of all variables in the query string (eg: someScript.php?x=1&y=2)
• $_REQUEST contains a merge of $_POST, $_GET and $_COOKIE (usually in that order). I don't recommend using this: you should know the methods you're using to get variables into your script and use that array specifically.

In your case, you need to take a look at the $_POST array. It's always handy to run this once:

print_r($_POST);

This will show you everything posted to that page.