结果中有两个数对不上

Question

import os
import sys


# 请在此输入您的代码
def fun(big_list, j, k):
    count = 0
    try:
        if big_list[j - 1][k] == 1:
            count += 1
    except:
        pass
    try:
        if big_list[j - 1][k - 1] == 1:
            count += 1
    except:
        pass
    try:
        if big_list[j - 1][k + 1] == 1:
            count += 1
    except:
        pass
    try:
        if big_list[j][k - 1] == 1:
            count += 1
    except:
        pass
    try:
        if big_list[j][k + 1] == 1:
            count += 1
    except:
        pass
    try:
        if big_list[j + 1][k - 1] == 1:
            count += 1
    except:
        pass
    try:
        if big_list[j + 1][k] == 1:
            count += 1
    except:
        pass
    try:
        if big_list[j + 1][k + 1] == 1:
            count += 1
    except:
        pass
    return count


n, m = map(int, input().split())
list_big = []
for i in range(n):
    list_big.append(list(map(int, input().split())))
j, k = 0, 0
list_input = []
for j in range(n):
    list0 = []
    for k in range(m):
        if list_big[j][k] == 1:
            list0.append(str(9))
            continue
        count = fun(list_big, j, k)
        list0.append(str(count))
    list_input.append(list0)
for item in list_input:
    str0 = " ".join(i for i in item)
    print(str0)

这个是我的输出结果

Answer 1

你存在的问题是当索引为-1时,python会取最后一位索引,而不是报错,所以会取到错误数据,需要进行边界判断

def fun(big_list, j, k):
    count = 0
    m = len(big_list)
    n = len(big_list[0])
    for x in range(-1, 2):
        for y in range(-1, 2):
            row = j + x
            col = k + y
            if (x | y) != 0 and 0 <= row < m and 0 <= col < n and big_list[row][col] == 1:
                count += 1
    return count