java编程职工信息

Question

用java写一个职工信息管理系统！
真的不会 大二实验题 有没有人会啊

Answer 1

1. 定义职工类
   类名称: Employee
   属性: 工号（id）、姓名（name）、性别（gender）、年龄（age）、职称（title）、基本工资（base_salary）
2. 创建职工对象集合
   创建了一个名为 employees 的列表，其中包含了5个 Employee 类的实例（职工对象）。
3. 保存职工信息到文件
   文件名: 2211050533.dat
   使用 pickle 模块，将 employees 列表（所有职工信息）保存到文件中。
4. 从文件读取职工信息
   从 2211050533.dat 文件中读取职工信息。
   将读取的信息显示在控制台上。
5. 计算平均年龄
   计算职工的平均年龄并在控制台上显示。
6. 统计年龄低于平均年龄的职工
   找出年龄低于平均值的职工。
   将这些职工的信息显示在控制台上。
7. 按年龄降序排列职工
   将职工按年龄降序排列。
   在控制台上显示排序后的职工信息。
8. 保存排序后的职工信息到新文件
   文件名: SunLinQin.dat
   将排序后的职工信息保存到新文件中。
   这个流程涵盖了从创建职工对象到数据的存储、处理和输出的全过程。
   下面是代码:

import pickle

# Define the Employee class
class Employee:
    def __init__(self, id, name, gender, age, title, base_salary):
        self.id = id
        self.name = name
        self.gender = gender
        self.age = age
        self.title = title
        self.base_salary = base_salary

    def __repr__(self):
        return f"ID: {self.id}, Name: {self.name}, Gender: {self.gender}, Age: {self.age}, Title: {self.title}, Base Salary: {self.base_salary}"

# Create a list of employees
employees = [
    Employee("001", "Alice", "Female", 30, "Manager", 5000),
    Employee("002", "Bob", "Male", 25, "Engineer", 4000),
    Employee("003", "Charlie", "Male", 40, "Technician", 4500),
    Employee("004", "Diana", "Female", 35, "Supervisor", 4800),
    Employee("005", "Evan", "Male", 28, "Clerk", 3500)
]

# Save the employee data to a file
filename = "2211050533.dat"
with open(filename, "wb") as file:
    pickle.dump(employees, file)

# Read the employee data from the file
with open(filename, "rb") as file:
    loaded_employees = pickle.load(file)

# Display the loaded employees
for employee in loaded_employees:
    print(employee)

# Calculate and display the average age
average_age = sum(emp.age for emp in loaded_employees) / len(loaded_employees)
print(f"Average Age: {average_age}")

# Find and display employees younger than the average age
younger_employees = [emp for emp in loaded_employees if emp.age < average_age]
print(f"Employees younger than the average age ({average_age}):")
for emp in younger_employees:
    print(emp)

# Sort employees by age in descending order and display
sorted_employees = sorted(loaded_employees, key=lambda emp: emp.age, reverse=True)
print("Employees sorted by age in descending order:")
for emp in sorted_employees:
    print(emp)

# Save the sorted employees to a new file
sorted_filename = "SunLinQin.dat"
with open(sorted_filename, "wb") as file:
    pickle.dump(sorted_employees, file)