duanlanzhi5509 2017-01-19 10:22
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组表值并将其他值相加

I have a mysql table with messages in. Each message has a status on its current status in the system. We want to generate charts comparing open messages vs the rest. I am trying to create a JSON response that looks as follows:

Roofing: [
   open: 12,
   others: 24
],
Building: [
   open: 4,
   others: 32
]

This is how the mysql database looks

+---+------------+---------+
|ID |  Industry  | Status  |
+---+------------+---------+
| 1 |  Building  | Sent    |
| 2 |  Building  | Review  |
| 3 |  Building  | Open    |
| 4 |  Roofing   | Sent    |
| 5 |  Roofing   | Review  |
| 6 |  Roofing   | Open    |
+---+------------+---------+

Sent and Review all fall under others

I need a way to count all the values for open and others and then lay it out in JSON.

Thanks for any help in advance.

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1条回答 默认 最新

  • dqx24298 2017-01-19 10:27
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    An often overlooked feature of COUNT is that it actually counts NON null values only

    SELECT industry, 
      COUNT(CASE WHEN Status  ='Open' THEN 1 ELSE NULL END) as open_count, 
      COUNT(CASE WHEN Status !='Open' THEN 1 ELSE NULL END) as other_count
    
      FROM Table1 GROUP BY industry
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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