通过PHP中的foreach进行验证

Question

Hi can some one help me out with the following. This prints every time Empty! or Full! whenever there is a blank or a non blank text box is detected.

What I need is the following;

1. Out of the series of text boxes (in the array) even only one text is detected blank just echo Empty! ONLY ONCE not every time there a blank textbox.

2. If ONLY all the text boxes are non-blank, then echo Full! only ONCE!

How do you suggest that I change the following? Thank you.

if(isset($_POST['Save']))
{
    if(is_array($_POST['name']))
    {
    foreach($_POST['name'] as $Value)
        {if($Value == '')
            {
            echo "<table border='1'><tr><td>Response</td></tr></table>";
            echo "Empty!";
            } 
            else 
            {
            echo "<table border='1'><tr><td>Response</td></tr></table>";
            echo "Full";
            }
        }
    }
}

EDIT

echo "<td><input style='width:60px' type='text' name='name[]' id='vtext' class='sc_two'     size='80' maxlength='5'></td>

then in a validation code I have the following;

if(isset($_POST['Save']))
{
    if($_POST['name']=='')
    {
    echo "<table border='1'><tr><td>Responses</td></tr></table>";
    echo "Empty";} 
    else 
    {
    echo "<table border='1'><tr><td>Responses</td></tr></table>";
    echo "Saved!";}
}

Answer 1

if(isset($_POST['Save'])) {
    if(is_array($_POST['name'])) {

        $result = 'Full!'; // Result defaults to 'Full!'

        // But if we find an empty value we change it to 'Empty!'
        foreach($_POST['name'] as $value){
            if($value === ''){
                $result = 'Empty!';
                break;
            }
        }

        // Output the response
?>
        <table border="1"><tr><td>Response</td></tr></table>
        <?=$result?>
<?php
    }
}