dtcu5885 2011-07-13 20:43
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带有括号的php regex环绕字符串,除非已被非文字括号包围

I have some code that is augmenting a regular expression by combining horizontal white-space and surrounding it in parentheses, unless it is already surrounded by non-backslashed parentheses. I have a piece of code that's working:

$regex_find = preg_replace('/(?<!\()[ \t]{2,}(?!\))/', '([ \t]{2,})', $regex_find);

However, for starters, the look-behind segnment, (?<!\(), should really allow for a literal left parenthesis, \(, but not a stand-alone left parenthesis, (.

Thanks

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  • duanao2585 2011-07-13 22:09
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    Your original regex also has another problem. Try running it on this:

     $str = "asdf(     )sdf     sdf";
     //results in: "asdf( (   ) )sdf(     )sdf"
    

    This regex should work:

    $regex_find = '(    asdf(     )sdf     sdf';
    preg_replace('/(?<!(\(|\s)(?=\s*\)))\s{2,}/','($0)',$regex_find);
    //result = "((    )asdf(     )sdf(     )sdf"
    

    Edit: Here is Qtax's solution with the additional lookbehind to ignore escaped \(

    /(?<!((?<!\\)\(|\s)(?=\s*\)))\s{2,}/
    
    评论

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