dtwxt88240 2017-11-29 10:09
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laravel 5.5从存储中获取文件URL

I am working on a project in which i want to get the link of the file which i uploaded in the storage-app-public directory of laravel. I followed this link StackOverflow question, but when I try to run following command in Vagrant:

php artisan storage:link

It gives following error:

[Symfony\Component\Console\Exception\CommandNotFoundException]
There are no commands defined in the "storage" namespace.
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  • dongxian8048 2017-11-29 10:49
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    you need to follow this code, I think It will be helpful for you.

    $imageTempName = $userdata->file('image_media')->getPathname();
    $imageName = $userdata->file('image_media')->getClientOriginalName();
    

    upload the file to the database within the directory using Laravel.

    <?php
    public static function upload_file(Request $userdata){
        $imageTempName = $userdata->file('image_media')->getPathname();
        $imageName = $userdata->file('image_media')->getClientOriginalName();
        $path = base_path() . '/public/uploads/images/';
        $userdata->file('image_media')->move($path , $imageName);
        $data=array('media'=>$imageName);
        $insert=with(new UserModel)->uploadFile($data);
    }
    ?>
    
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