PHP生成表单的输入未被记录

Question

The issue I have been experiencing deals with input from HTML which was generated using PHP echo statements. Here is the function I have that outputs the form:

function confirm_recipients()
    {

        echo "<form action = ' ' name ='email_options' method='post'>";
        echo "<input type='submit' name='sendRecipients' value='Yes, I want to send the emails' >";
        echo "</form>";
    }

Later on in the same PHP page, I call the function and then check to see if the submit button was set.

confirm_recipients();

if (isset($_POST['sendRecipients'])) 
    {
    //perform actions
    }

However, this code is not functional seeing as even when the submit button is set (clicked by the user), the if statement block is never executed. Perhaps there is an issue with posting from the same file I want to "read in" from? Thanks for any advice.

Updates

Thank you for such immediate response. Sadly none of the suggestions have worked (removing the space in the action value or the suggestion made by user623952). No errors have been reported, the button is just failing to be set. I am looking for other places in the file that might have errors, perhaps in the order I call the function.

Answer 1

This works fine for me:

<?php

print "<pre>".print_r($_POST,true)."</pre>"; 

confirm_recipients();

function confirm_recipients() { 
    echo "<form action = ' ' name ='email_options' method='post'>";
    echo "<input type='submit' name='sendRecipients' value='Yes, I want to send the emails' >";
    echo "</form>";
}


if (isset($_POST['sendRecipients']))
{
    print "<br/>sendRecipients is set!<br/>"; 
}

?>

I think your problem might be somewhere else in the code.