在PHP中的数字到单词转换（印度卢比）十进制字符串问题

Question

I using Following function to convert numbers to word Conversion in PHP.

I Expected Result.

one thousand five hundred and forty two Rupees twenty six Paise Only

but, its Display

one thousand five hundred and forty two Rupees two six Paise Only

My Function is :

function displaywords($number){
   $no = round($number);
   $point = round($number - $no, 2) * 100;
   $hundred = null;
   $digits_1 = strlen($no);
   $i = 0;
   $str = array();
   $words = array('0' => '', '1' => 'one', '2' => 'two',
    '3' => 'three', '4' => 'four', '5' => 'five', '6' => 'six',
    '7' => 'seven', '8' => 'eight', '9' => 'nine',
    '10' => 'ten', '11' => 'eleven', '12' => 'twelve',
    '13' => 'thirteen', '14' => 'fourteen',
    '15' => 'fifteen', '16' => 'sixteen', '17' => 'seventeen',
    '18' => 'eighteen', '19' =>'nineteen', '20' => 'twenty',
    '30' => 'thirty', '40' => 'forty', '50' => 'fifty',
    '60' => 'sixty', '70' => 'seventy',
    '80' => 'eighty', '90' => 'ninety');
   $digits = array('', 'hundred', 'thousand', 'lakh', 'crore');
   while ($i < $digits_1) {
     $divider = ($i == 2) ? 10 : 100;
     $number = floor($no % $divider);
     $no = floor($no / $divider);
     $i += ($divider == 10) ? 1 : 2;


     if ($number) {
        $plural = (($counter = count($str)) && $number > 9) ? 's' : null;
        $hundred = ($counter == 1 && $str[0]) ? ' and ' : null;
        $str [] = ($number < 21) ? $words[$number] .
            " " . $digits[$counter] . $plural . " " . $hundred
            :
            $words[floor($number / 10) * 10]
            . " " . $words[$number % 10] . " "
            . $digits[$counter] . $plural . " " . $hundred;
     } else $str[] = null;
  }
  $str = array_reverse($str);
  $result = implode('', $str);


  $points = ($point) ?
    "" . $words[$point / 10] . " " . 
          $words[$point = $point % 10] : ''; 

  if($points != ''){        
  echo $result . "Rupees  " . $points . " Paise Only";
} else {

    echo $result . "Rupees Only";
}

}

$ins=1542.26;

echo displaywords($ins);