使用PHP在CSS中搜索内容

Question

I have that in a variable :

.fontSize10{
font-size:xx-small;
}
.fontSize11{
font-size:x-small;
}
.fontSize12{
font-size:small;
}
.fontSize13{
font-size:medium;
}
.fontSize14{
font-size:large;
}
.fontSize16{
font-size:x-large;
}
.fontSize18{
font-size:xx-large;
}

In this variable, i can have a lots of other css instructions.

I need to retrieve, for each instructions that begin by .fontSize, his name (for example .fontSize14) and his size (large).

I need to keep name and size together (in an array for example $tab[0][0] = "fontSize14" and $tab[0][1] = "large")

Do you have an idea ? With regex maybe ? Thanks :)

Answer 1

If it strictly keeps to this format, you could do it with a regular expression like this:

=\.(fontSize\d+)\s*\{\s*font-size:([^;]+);\s*\}=is

However, I would advise you to write a proper parser so you can deal with wrong or different formats. Meaning that you iterate through the string line by line and store in a variable the name of the current definition block. If you encounter a font-size: you can just add the found value to an array using the name of the current block. When you encounter a closing bracket, you just set the variable back to null. It will be much more robust than the regular expression, because it works for CSS definitions with more attributes just as well.