如何在php中删除两个日期[重复]

Question

This question already has an answer here:

• How to calculate the difference between two dates using PHP? 32 answers

I want to subtract the datenow and the registerdate and use the result in a condition.

Following is the code:

    public function actionCheckDate(){
        date_default_timezone_set('Asia/Kuala_Lumpur'); 
        $datenow = date('Y-m-d');   

        $id = Yii::app()->user->getState('id');
        $models = GamesDevelopers::model()->find('id='.$id); 
        $registerdate = CHtml::encode($models->registerdate);           
        $active = strtotime($datenow)-strtotime($registerdate);

        print_r($active);
        die();
}

The result is : 627173 , how I gonna to know that 627173 is how many time or date ?

UPDATED

    public function actionCheckDate(){
        date_default_timezone_set('Asia/Kuala_Lumpur'); 
        $datenow = date('Y-m-d H:i:s'); 

        $id = Yii::app()->user->getState('id');
        $models = GamesDevelopers::model()->find('id='.$id); 
        $registerdate = CHtml::encode($models->registerdate);           

        $diff = abs(strtotime($registerdate) - strtotime($datenow));

        $years = floor($diff / (365*60*60*24));
        $months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
        $days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));

        printf("%d years, %d months, %d days
", $years, $months, $days);
        die();
}

Worked fine but how to count hours ?

To find hours:

    $hours = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24)*24);

    printf("%d hours
",$hours);

</div>

Answer 1

Timestamp difference is in seconds. You can convert this into minutes(divide by 60), hours (divide by 60*60), day (divide by 24*60*60) & so on.

There are lots of examples & tutorials given on the web, please refer:

http://www.w3schools.com/php/func_date_date_diff.asp

How to calculate the difference between two dates using PHP?

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