在PHP中作为非字符串参数的类

Question

Example in file 1:

namespace A;

class Foo{

}

file 2:

use A\Foo;

do_stuff('A\Foo');  // <- need namespace here :(

Foo::someStaticMethod();  // <- namespace not required :D

Is there any way I can pass class names in function arguments like constants or something, so I don't need to prepend the namespace?

Answer 1

Update :)

When I know, that I need to pass the classnames of some classes around as string I'm used to create special class constant

namespace Foo\Bar;
class A {
    const __NAMESPACE = __NAMESPACE__;
    const __CLASS = __CLASS__;
}

Now you can reference the classname like

use Foo\Bar\A as Baz;
echo Baz::__CLASS;

With PHP5.5 this will be builtin

echo Baz::class;

---

Full-Qualified-Names (FQN) for namespaces always starts with a namespace separator

do_stuff('\A\Foo');

except (and thats the only exception) in use-statements, because there can only appear complete namespace identifiers, so for convenience you can omit it there.

However, a string is a string and where you use it as a class name is out of scope of the interpreter, so it lost the reference to the former use A\Foo-aliasing. With PHP5.5 you can write Foo::class, but I think thats not an option right now ;)