变量赋值和函数 - 这应该工作正常吗？

Question

I am trying to take a variable from $_POST, run mysql_real_escape_string and a custom function, html2text on it. This should work, right? Or do I need to separate it on separate lines?

$orgname = mysql_real_escape_string(html2txt($orgname)) = $_POST['orgname'];

Answer 1

Are you trying to do this:

$orgname = mysql_real_escape_string(html2txt($_POST['orgname']));