如何将作为mysql查询结果返回的列名的所有行存储在字符串数组中

Question

I want to store all rows of a column name returned as a mysql query result in a string array. I am new to php. I have retrieved the rows but how do I store all rows of a column in an array? I mean how to iterate the counter of rows and store the column in an array? Or is there any direct function/method call? Please see my code below and its possible ways of storing in an array:

$dbhost = 'localhost';
$dbuser = 'user';
$dbpass = 'password';

$conn = mysql_connect($dbhost, $dbuser, $dbpass) or die('Error connecting to mysql');
$dbname = 'users';
mysql_select_db($dbname);

$result = mysql_query("SELECT users.email FROM users");

//  AND THEN FINALLY STORING IN A STRING ARRAY:

$array = $result;

//  OR SOMETHING LIKE:

Store($array, $result);

//  OR SOMETHING LIKE:

for(int i = 0; i < $result.Rows.Count; i++)
{
    if (null != $row[0])
    {
        $array[i] = $result[i];
    }
}

//  OR SOMETHING LIKE:

while($null != result.read())
{
    $array.Add($result.Read());
}

Please help me in writing the code.

Answer 1

MySQL Fetch Array

$result = mysql_query("SELECT users.email FROM users");

while($row = mysql_fetch_array($result)){
    $array[] = $row;
}

This will return an array of associated arrays. The $row will contain the index of the column name along with integer index.

For example:

echo $row['email'];
//or
echo $row[0];

In the end you can get the first row by:

$array[0]['email']; //or $array[0][0];

NOTICE: Do not use MySQL_* for it has been deprecated as of PHP 5.5. Use MySQLi_* or PDO instead.