dongxie1907 2016-07-28 14:45
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Gmail代理电子邮件中忽略了PHP参数

I am sending a PHP image through email that uses parameters to determine the image to display. This image displays in every email client except Gmail. The reason for this is due to the Google User Content Proxy, which wraps around the link and shows the php file while ignoring the parameters attached to it.

I seem to have the same problem as this question, Problems with tracking pixels and Gmail proxy. Their solution was the following:

I resolved it using https://www.example.com/tracking.php/order_id=1 instead and then on the tracking.php I didn't use $_GET but $_SERVER['REQUEST_URI'] and parsed the /order_id= String.

The problem is I don't understand how to do this.

When I visit the file URL for test.php?par=1, I am able to pull par using $_GET. If I switch the file URL to test.php/par=1, I receive a 404 error.

How do I use /par=1 as my parameter while still accessing test.php first so I can pull the whole url using $_SERVER['REQUEST_URI']?

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  • douzhuo5671 2016-07-28 14:52
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    test.php?par=1 is a script named test.php with a query string key of par and value 1.

    If you do not have pathinfo enabled, then test.php/par=1 is a DIRECTORY name test.php, and a non-existent file in that directory named par=1.

    Note that PHP won't parse pathinfo data into $_GET. Only actual ?key=val-type query values are processed for that. You'll have to dig out $_SERVER['PATH_INFO'] and parse it yourself.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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