PHP日期返回到下一个星期一的错误天数

Question

Im trying to calculate number of days left to next monday and it returns 10, Im sure its wrong, days left to next monday is 5, what im doing wrong?

 if (isset($_POST['entry'])) {


  $email=mysql_real_escape_string($_POST['email']);
  $t_shirt=mysql_real_escape_string($_POST['t-shirt']);
  $today = date("m.d.Y");
  $next_monday = date("d, m, Y", strtotime('next monday'));
  $last_monday = date("d, m, Y", strtotime('last monday'));
  $today = date("d.m.Y");


  $select_current=mysql_query("SELECT * FROM entry_form WHERE email='$email'");
   if (mysql_num_rows($select_current) >= 1) {
   while ($row=mysql_fetch_array($select_current)) {

    $last_registered=$row['registered'];

    } 

    $diff = abs(strtotime($last_registered) - strtotime($last_monday));
    $years = floor($diff / (365*60*60*24));
    $months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
    $days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));

    echo "$days";

     }

Answer 1

You making it to difficult for your self, already asked that question on calculating date_diff:

 //get today's timestamp
 $date_now = date_create("today");

 //get next monday date
 $mon_date = date_create("next monday");

 //calculate date difference
 $difference = date_diff($mon_date,$date_now);

 $int = intval($difference->format('%a'));
 echo $int;