duan7264 2013-03-19 13:58
浏览 27
已采纳

试图在div中获取MySQL数据

I'm trying to get specific content from every single row in my MySQL database inside a div, however it only shows content from the row with the highest id value.

mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");

$query = "SELECT * FROM articles ORDER BY id";
$result = mysql_query($query) or die(mysql_error());

$count = mysql_num_rows($result);

while($row = mysql_fetch_array($result))
{
    $title = $row['title'];
    $summary = $row['summary'];
}
?>

<div class="content">
    <h2 class="titlecss"><?php echo ($title)?></h2>
    <p class="customfont"><?php echo ($summary)?></p>
</div>

Could anyone explain what I'm doing wrong here? I've been browsing the internet for 2 hours but can't seem to find anything...

  • 写回答

2条回答 默认 最新

  • dqy012345 2013-03-19 14:01
    关注

    You need to output each div inside the while loop:

    while($row = mysql_fetch_array($result))
    {
        $title = $row['title'];
        $summary = $row['summary'];
        ?>
        <div class="content">
        <h2 class="titlecss"><?php echo ($title)?></h2>
        <p class="customfont"><?php echo ($summary)?></p>
        </div>
        <?php
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(1条)

报告相同问题?

悬赏问题

  • ¥15 乌班图ip地址配置及远程SSH
  • ¥15 怎么让点阵屏显示静态爱心,用keiluVision5写出让点阵屏显示静态爱心的代码,越快越好
  • ¥15 PSPICE制作一个加法器
  • ¥15 javaweb项目无法正常跳转
  • ¥15 VMBox虚拟机无法访问
  • ¥15 skd显示找不到头文件
  • ¥15 机器视觉中图片中长度与真实长度的关系
  • ¥15 fastreport table 怎么只让每页的最下面和最顶部有横线
  • ¥15 java 的protected权限 ,问题在注释里
  • ¥15 这个是哪里有问题啊?