douwan2664 2015-04-12 19:20
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Laravel 5 Pagination CSS Breaking

I'm using Laravel 5 and Bootstrap 3.3.4

So I have the following code in my controller:

$articles = Newsarticles::paginate(10);
return view ('news',compact('articles');

Then in my view I have:

@foreach($articles as $article)

<article>
    <h2>
        <a href="{!! action('DynamicPages@show', [$article->slug]) !!}">{!! $article->headline !!}</a>
    </h2>
    <div class="body">
        {!! substr($article->article,0,500) !!}
    </div>
</article>

@endforeach

{!! $articles->render() !!}

When I run this, the pagination links at the bottom of the page come out just fine and look as they should do. However, if I change the controller to :

$articles = Newsarticles::orderBy('artdate','DESC')->paginate(10);

my pagination links come out like this:

«
1
2
3
4
5
6
»

How can one small adjustment in the code break the css?

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4条回答 默认 最新

  • doujiayao8433 2015-04-12 19:50
    关注

    With substr($article->article,0,500) you may breack html code.

    You can also have a distinct number of vivible chars

    p>hello</p>

    12 chars

    <stong>hello</strong>

    21 chars.

    And take care of this:

    echo substring('<p>hello</p>', 5);
    

    Writes: "

    he". Breack html result.

    Try with

    substr(strip_tags($article->article,0,500))

    to strip all html tabs before cut the string. This will not breack your current html and you will get the correct chars length.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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