内容中的正则表达式匹配

Question

I want to match the following string with a regular expression:

$string ="test string [% code content ='test content' class ='myclass' %]";

I want to extract the class and content from this string in percentage braces. Iam using this pattern for matching

$regex_pattern = "/[% ?.*](.*)[\/%]/";
preg_match_all($regex_pattern,$content,$matches);

but not getting the output that I require.

Answer 1

You can use the regex to capture contents and class values regardless of their positions inside the [% ... %]:

(?:content|class)\s*='([^']+?)'(?=(?:(?!\[\%|\%\]).)*?\%\])

See demo.

<?php
    $re = "/(?:content|class)\\s*=\\s*'([^']+?)'(?=(?:(?!\\[\\%|\\%\\]).)*?\\%\\])/"; 
    $str = "test string [% code content ='test content' class ='myclass' %]"; 
    preg_match_all($re, $str, $matches);
    echo $matches[1][0] . "
";
    echo $matches[1][1] . "
";
?>

Here is a sample program.

Output:

test content                                                                                                                                                                                                                                           
myclass