PHP数组问题？

Question

Hope you are fine. My question :

In MYSQL i have a table with this type of field

Field Name: TAGS Value : xavier,celine,marise,leon,john,cathy,polux,maurice

---

In PHP i do this

$xwords = array();
function array_rpush(&$arr, $item)
{
  $arr = array_pad($arr, -(count($arr) + 1), $item);
}

$tags = requete("SELECT tags FROM tbl_tags LIMIT 1;");
while($dtags = mysql_fetch_assoc($tags)){
  $words .= array_rpush($xwords, $dtags['tags']);
}

// MY ARRAY XWORDS FOR DEBUG
//
// Array ( [0] => xavier, celine, marise, leon, john, cathy, polux, maurice
//

My script need to find the first letter of each word in this list and check if he match with A / B / C (i create an A-Z index page)

// COUNT $XWORDS VALUE
$total = count($xwords);
// total =1
for($i=0; $i < $total; $i++)
{
 $wtags = explode(",",$xwords[$i]);
 // wtags = Array ( [0] => xavier [1] => celine [2] => marise... )
  while (list($idx,$val) = each($wtags)) {
    echo $val{0}."<br>";
    echo substr($val,0,1)."<br>";
  }
}

echo $val{0}."<br>"; OR echo substr($val,0,1)."<br>" give me just x and nothing after (while give me only the first letter for the first record in array... amazing :))

Perhaps you can help me find a solution. Thanks

Answer 1

The problem with your code is that it generates:

Array ( [0] => "xavier" [1] => " celine" [2] => " marise"... )

So $val[0] = " ". Try to trim($val):

$val = trim($val);
print $val[0];