donglun1918 2017-11-27 09:53
浏览 47
已采纳

通过继承的静态方法创建继承类的新实例

I've got a method in my class to create a new 'self' on execution.

class foo {
    private $id;

    public function __construct( $id ) {
        $this->id = $id;
    }

    public static function byId( $id ) {
        return new self( $id );
    }  

}

And now i want to use the byId method from foo and use it in bar, by doing as such

class bar extends foo {
    public function test() {
        echo "test";
    }
}  

now I should be able to do bar::byId( id ), however this will always return the parent object and not the bar object.

How can i make sure that byId will return the object of the inherited class if it's called through it?

  • 写回答

1条回答 默认 最新

  • douzhi2988 2017-11-27 10:07
    关注

    Use return new static($id); instead of return new self($id);

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 加氢站氢负荷数据集来源
  • ¥15 umi接入sentry遇到问题
  • ¥15 HBuilderX打包H5网页,扫码模块无法使用
  • ¥15 Javascript跳转页面后,无法执行后面代码,如何解决?
  • ¥15 echarts绘制图表
  • ¥15 请教两个关于高德地图定位不准的技术问题
  • ¥15 根据企业名称 对照两个文件 样本筛选/匹配
  • ¥15 Linux环境下CA证书更新问题
  • ¥15 sqlserver语句提取结果以外数据
  • ¥60 微信小程序如何上传QQ聊天文件