dozug64282 2016-02-16 17:44
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如何使用PHP回显基于MySQL数据库的动态html片段?

I'm trying to create an image gallery with a for loop iterated by a counter of database rows. To make it more clear: for each row in the table, get only the id(primary index) number and the image link from the server (not all the info in the row). With that information, echo an HTML image tag with the link inside the 'src=' and the id inside the 'alt='.

Two problems here:
1- the id number of the first row isn't zero.
2- I don't have a clue on how to get the total number of rows and to fetch only those two informations (id and img source).

That way, I could subtract the total number of rows minus the id number of the first row and using it to put an end on the loop.

So how to echo this dynamic html snippet based on my databse with PHP?

My code:

<?php

$link = mysqli_connect('localhost','user','pass','db');
$result = mysqli_query($link, "SELECT * FROM `table`");
$rows = mysqli_num_rows($result);

/* free result set */
mysqli_free_result($result);

$caption = mysqli_query($link, "SELECT ");

for($i=0; $i < $rows; $i++) {
    echo "<img src='$imageURL' alt='$idNumber'>";
}

?>
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  • dongshen9058 2016-02-16 18:48
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    This is a really easy task.

    First we fetch the data from the database using mysqli_query to do the query.

    Then we use mysqli_fetch_array to get an array so then we can loop through it and echo each item.

    After that, we mysqli_num_rows to get the total number of rows returned and increment it by 1 so it is not zero.

    NOTE: Since you are going to increment the id to avoid getting a '0', don't to forget to minus '1' if you intend to use that id for some server-side purpose.

    $result = mysqli_query($link, "SELECT * FROM `table`"); //query sql
    $result_array=mysqli_fetch_array($result, MYSQLI_ASSOC);//return array from the query
    $count = mysqli_num_rows($result);                      //get numbers of rows received 
    
    foreach($result as $row){ //do a foreach loop which is really simple
        echo "<img src='". $row['img_column_name_from_db'] . "'  alt='" .$row['id_column_name_from_db'] + 1 . "'>"; //echo data from the array, + 1 to "$row['id_column_name_from_db']" so that 'alt=' doesn't start from '0'.
        } 
    echo $count;
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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