创建自定义值在Laravel中的辅助方法中选择查询

Question

i am trying to create a something like below, in my Laravel 5.1 project within helper.php.

$result = App\Pages::where('id', $id)->where('active', 1)->first();

here is how my helper.php looks like:

<?php
namespace App\Helpers;
use App;
class Helper
{
        public static function checkSlug($subject, $id, $inputSlug = null){
            $result = App\$subject::where('id', $id)->where('active', 1)->first();
            return $result;
        }
}
?>

My Helper class seems working fine. But i am stuck in this line App\$subject::where('id', $id)->where('active', 1)->first();. When i pass the variable $subject i get this below error:

parse error, expecting `"identifier (T_STRING)"'

And here is how i am using my helper method in my view

{{Helper::checkSlug('Pages', $page->id)}}

Now when i am trying to access my Model using App\$subject its not allow. I guess.

Any suggestions will be helpful. Thank you!

Answer 1

I mean you can't use variable classes with static methode syntax. But you can instantiate your model:

public static function checkSlug($subject, $id, $inputSlug = null)
{
    $clsname = 'App\\' . $subject;
    $cls = new $clsname();
    $result = $cls->where('id', $id)->where('active', 1)->first();
    return $result;
}

and with the object build your query and get your row or not.