doushan6161 2016-09-24 17:46
浏览 113

表格不通过POST发送数据

I have this code (it's an include), but the thing is that when I send the form the $_POST data is not being sent. Im checking for $_POST data like this

if(isset($_POST['ft_upload']) && $_POST['ft_upload'] == 1){
    //$usuario -> uploadFirstTime2($db);
    echo "ok";
}

and the code for the form is

<div class="ft_userImage" style="background: url(<?php echo $usuario -> getProfileImage(); ?>);"></div>


<p class="ft_step2_continue"><?=$TEXT_BUTTONS['continue'];?></p>

<form action="" method="POST" class="ft_step2_form_upload">
    <input type="hidden" name="ft_upload" value="1" />
</form>

<script>
    $("p.ft_step2_continue").click(function(){
        $(".ft_step2_form_upload").submit();
    });
</script>
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4条回答 默认 最新

  • dongtong5242 2016-09-24 18:00
    关注

    check.php

    <?php
   if(isset($_POST['ft_upload']) && $_POST['ft_upload'] == 1) {
      echo "ok";
   }   
?>

    index.html

    <!DOCTYPE html>
<html>
<head>
    <title>form</title>
</head>
<body>
<form action="check.php" method="POST" class="ft_step2_form_upload">
    <input type="hidden" name="ft_upload" value="1" />
</form>
    <button id="ft_step2_continue">SEND</button>
    <script type="text/javascript" src="https://code.jquery.com/jquery-1.12.4.min.js"></script>
<script>
    $("#ft_step2_continue").click(function(){
        $(".ft_step2_form_upload").submit();
    });
</script>
</body>
</html>

    it works fine.

    i think, you just forgot action="check.php" in your form tag.

    评论

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