解析一个文本文件并得到一个数组类型的数组（“（0:00）”=>“text1”，“（0：30）”=>“text2”）

Question

I have a text file

(0:00)

text1

text2

(0:30)

text text text text text

..................

the result should be like this

array("(0:00)"=>"text1 text2","(0:30)"=>"text text text text text") 

my code

$key = array();
    $val = array();
    $out = array();
    $file = file('1.txt');
    foreach($file as $line) {
        $line = trim($line);
        if (preg_match("/(\d{0,2}:\d\d)/",$line,$match)){
            $key[]=$match;
        }else{
            $val[]=$match;
        }
        $out=array_merge($key,$val);
    }
    echo '<pre>';
    print_r($out);

tell me, how to fix it?

Answer 1

$text = file_get_contents('1.txt');
preg_match_all("~\(\d{1,2}:\d{1,2}\)~", $text, $keys);
$values = array_values(preg_grep("~.+~", preg_split("~\(\d{1,2}:\d{1,2}\)~", $text)));
$final = [];
for ($n = 0; $n < count($keys[0]); $n++) {
    $final[$keys[0][$n]] = $values[$n];
}
print_r($final);