来自json的android中的Php没有发布到表中，我的代码中有什么问题吗？

Question

I have an android app converting info into JSON and sending it to php/MySQL, get response back on the phone just fine but nothing is getting into the table, I'm not that experienced in php, did I screw up this code?

<?php
include('../htconfig/dbConfig.php'); 
$dbSuccess = false;
    $dbConnected = mysql_connect($db['hostname'],$db['username'],$db['password']);

    if ($dbConnected) {     
        $dbSelected = mysql_select_db($db['database'],$dbConnected);
        if ($dbSelected) {
            $dbSuccess = true;
        }   
    }
$data_back = json_decode(file_get_contents('php://input'));


$userName = $data_back->{"User"};
$password = $data_back->{"Pword"};
$PurchasedFrom = $data_back->{"Pfrom"};
$VIN = $data_back->{"VIN"};
$Color = $data_back->{"Color"};
$MakeIndex = $data_back->{"Make"};
$ModelIndex= $data_back->{"Model"};
$Year = $data_back->{"Year"};
$Bid = $data_back->{"Bid"};
$INV = $data_back->{"PurchasePrice"};
$BidContact = $data_back->{"Contact"};
$BidEmail= $data_back->{"Email"};


mysql_query("Insert Into tblinventory (VIN, MakeIndex, ModelIndex, Year, Color,Bid,INV, 
BidContact, BidEmail, PurchasedFrom)
VALUES ('$VIN','$MakeIndex', '$ModelIndex', '$Year', '$Color', '$Bid', 
'$INV', '$BidContact', '$BidEmail', '$PurchasedFrom')");

$responses = array();
 {
    $responses[] = array( $VIN . " " . $MakeIndex . " " . $ModelIndex." ". $Year." " );
}


header("Content-type: application/json");


echo json_encode($responses);
?>

Answer 1

Needed to add error checking code and make sure there is an actual database connection. Also make sure your input and query have the same name..see PurchasedFrom and Pfrom. Thanks for the help guys and thanks for the links, they will help a lot. Happy Coding :)