dongzhan2029 2014-10-12 00:15
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I'm trying to get the image urls from html source code using the following regex, but it fails when the image url has spaces in it. For example this url:

<img src=" pink bikini reuters.jpg?ve=1&amp;tl=1" alt="kazantsev pink bikini reuters.jpg" itemprop="image">

$image_regex_src_url = '/<img[^>]*'.'src=[\"|\'](.*)[\"|\']/Ui';
preg_match_all($image_regex_src_url, $string, $out, PREG_PATTERN_ORDER);

This gives me back the following.

Is there a way to match any character including whitespace? Or is it something I have to set in the php configuration?

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  • donglu1973 2014-10-12 00:31

    You have several issues with your regular expression.

    First, you are trying to use the concatenation operator ('.') to join both parts of your expression together ( this is not necessary ). Secondly, you don't need to use the alternation operator | inside of your character classes.

    The dot . will match any character except newline sequence. It is a possibility that these tags could possibly include line breaks since they are located in HTML source. You could use the s (dotall) modifier which forces the dot to match any character including line breaks or use a negated character class meaning match any character except.

    Using the s (dotall) modifier:

    $image_regex_src_url = '/<img[^>]*src=(["\'])(.*?)\1/si';

    Using a negated character class [^ ]

    $image_regex_src_url = '/<img[^>]*src=(["\'])([^"\']*)\1/i';

    Although, it is much easier to use a parser such as DOM to grab the results.

    $doc = new DOMDocument;
    @$doc->loadHTML($html); // load the HTML
    foreach($doc->getElementsByTagName('img') as $node) {
       $urls[] = $node->getAttribute('src');
    本回答被题主选为最佳回答 , 对您是否有帮助呢?



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